Answer:
Step-by-step explanation:
Recall that we say that d | a if there exists an integer k for which a = dk. So, let d = gcd(a,b) and let x, y be integers. Let t = ax+by.
We know that 
so there exists integers k,m such that a = kd and b = md. Then,
. Recall that since k, x, m, y are integers, then (kx+my) is also an integer. This proves that d | t.
8 over 20 equals 6 over 15
Before we can solve this word problem, we have to translate first this problem into numerical form.
The sum of fifteen and six times a number t is 81 can be translated into
15 + 6t = 81
We can now solve this equation.
Let's add both sides of the equation by -15.
15 + 6t - 15 = 81 - 15
6t = 66
Divide both sides of the equation by 6.
6t / 6 = 66 / 6
t = 11
Therefore, the value of t is 11.
Hope this help yahhh!!
Answer: Y=2
Step-by-step explanation:
