Answer:(- 1/2, 1/2)
(- 1, 2)
Step-by-step explanation:
The given system of equations is expressed as
y = 2x²- - - - - - - - - - - - - - -1
y = - 3x - 1- - - - - - - - - -- - - -2
We would apply the method of substitution by substituting equation 1 into equation 2. It becomes
2x² = - 3x - 1
2x² + 3x + 1 = 0
We would find two numbers such that their sum or difference is 3x and their product is 2x². The two numbers are 2x and x. Therefore,
2x² + 2x + x + 1 = 0
2x(x + 1) + 1(x + 1) = 0
2x + 1 = 0 or x + 1 = 0
x = - 1/2 or x = - 1
Substituting x = - 1/2 into equation 1, it becomes
y = 2(-1/2)² = 1/2
Substituting x = - 1 into equation 1, it becomes
y = 2(-1)² = 2
I know how to solve it but the value of 'a' is required for solution.
First it is important to notice that the b is 6, h is 8 and l is? so we find l by using the trigonometry which gives us approximately 13, then we plug it in to V= 1/2 lbh= 1/2 (6)(8)(13)= 312 cm^3