The hole is located where the hole is part a
We know that
If the scalar product of two vectors<span> is zero, both vectors are </span><span>orthogonal
</span><span>A. (-2,5)
</span>(-2,5)*(1,5)-------> -2*1+5*5=23-----------> <span>are not orthogonal
</span><span>B. (10,-2)
</span>(10,-2)*(1,5)-------> 10*1-2*5=0-----------> are orthogonal
<span>C. (-1,-5)
</span>(-1,-5)*(1,5)-------> -1*1-5*5=-26-----------> are not orthogonal
<span>D. (-5,1)
</span>(-5,1)*(1,5)-------> -5*1+1*5=0-----------> are orthogonal
the answer is
B. (10,-2) and D. (-5,1) are orthogonal to (1,5)
X²-3x-10=0
x²-(5-2)x-10=0
x²-5x+2x-10=0
x(x-5)+2(x-5)
(x-5)(x+2)
Yes it is an irrational number
Answer:
Step-by-step explanation:
hello :
hello :
1) divid by 3 : 27:9= 9/3
2) 9/3 = 3/1
