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Papessa [141]
3 years ago
12

Use the three steps to solve the problem. the length of a rectangle is 2 inches less than 3 times the number of inches in its wi

dth. if the perimeter of the rectangle is 28 inches, what is the width and length of the rectangle?
Mathematics
1 answer:
Tems11 [23]3 years ago
3 0
Let the width of the rectangle be w.

Let the length be l.

l = 3w - 2

Given,

Perimeter = 28 

2*( l + w ) = 28

2*( 3w -2 + w ) = 28 

4w - 2 = 14  [ Dividing both sides by 2 ]

2w - 1 = 7 [ Dividing both sides by 2 ]

2w = 8

w = 4.

Thus,

l = 3w -2 = 3*4 - 2 = 12 - 2 = 10

Therefore, the length is 10 inches and the width is 4 inches.
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A triangle has the side lengths of 28 in,4in and31 inches. classify it as acute, obtuse or right
labwork [276]
The answer is obtuse

a = 4
b = 28
c = 31

If a² + b² > c²    -  the angle is acute
If a² + b² < c²    -  the angle is obtuse
If a² + b² = c²    -  the angle is right

a² + b² = 4² + 28² = 16 + 784 = 800
c² = 31² = 961

    800 < 900
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Therefore, the angle is obtuse
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Final Answer: 1.6

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