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Alex
3 years ago
10

Determine whether the triangles are similar by aa , ss , or sas ??

Mathematics
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

1. AA

2. SSS

3. I´m not sure about this one, I´m sorry

4. Not similar

Step-by-step explanation:

This photo can help you identify!! I hope this helps

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How much less is 17km than 24.6km?​
tatuchka [14]
24.6-17= 7.6 (km) i think so
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What is 9x-5x ????i need help
Dima020 [189]

Hi there!

Answer:

<u><em>=4x</em></u>

Step-by-step explanation:

Distributive property: ⇒ a(b+c)=ab+ac

You had to add similar elements.

9x-5x=4x

5x+4x=9x

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4 0
3 years ago
Help me pls math genius
Alecsey [184]

Answer:

x = -3

y = -1

Step-by-step explanation:

in the given question :-

=》x - 4y = 1

=》x = 4y + 1

now replacing the value of x as ( 4y + 1 ) in equation (2)

=》3x + 2y = -11

=》3 (4y + 1) + 2y = -11

=》12y + 3 + 2y = -11

=》14y = -11 - 3

=》y = -14 ÷ 14

=》y = -1

now, putting the value of y in equation (1)

=》x - 4y = 1

=》x - ( 4 × -1 ) = 1

=》x + 4 = 1

=》x = 1 - 4

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6 0
3 years ago
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A student is applying to Harvard and Dartmouth. If the student is accepted at Dartmouth, the probability of being accepted at Ha
adell [148]
I made a probability tree. Pls. see attachment. 

Based on the probability tree I made, below are the probabilities

Probability of a student accepted at both Dartmouth and Harvard is:
50% x 40% = 20%

Probability of a student accepted at Dartmouth but not Harvard is:
50% x 60% = 30%

Probability of a student not accepted at Dartmouth but accepted in Harvard is:
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Probability of a student not accepted in both schools is:
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6 0
3 years ago
Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
nirvana33 [79]

Answer:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}

And solving for \frac{dh}{dt} we got:

\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}

We need to convert the rate given into m^3/min and we got:

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

5 0
4 years ago
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