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alina1380 [7]
3 years ago
8

Sone for x and y

Mathematics
2 answers:
Aleksandr [31]3 years ago
7 0

Answer:

It's d. (16,21).

Step-by-step explanation:

2x -  y =  11 .............(1)

3x – 2y = 6...........(2)

Multiply the first equation by -2:

-4x + 2y = -22.......(3)

Adding (2) + (3):

-x = -16

x = 16.

Substitute for x in equation (1):

2(16)  - y = 11

-y = 11-32 = -21

y = 21.

ddd [48]3 years ago
4 0

Answer:

d

Step-by-step explanation:

Given the 2 equations

2x - y = 11 → (1)

3x - 2y = 6 → (2)

Multiply (1) by - 2 and adding will eliminate y

- 4x + 2y = - 22 → (3)

Add (2) and (3) term by term

(3x - 4x) + (- 2y + 2y) = (6 - 22)

- x = - 16 ( multiply both sides by - 1 )

x = 16

Substitute x = 16 into (1) or (2) for corresponding value of y

(1) : 32 - y = 11 ( subtract 32 from both sides )

- y = - 21 ( multiply both sides by - 1 )

y = 21

Solution is (16, 21 ) → d

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A baseball team had 28 hime runs last year. This year they have 20 homeruns. What was the percent of change
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Answer:

28.57% drop

Step-by-step explanation:

Number of runs

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  • This year = 20

Change this year:

  • 28 - 20= 8

Change %:

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The area of a rectangle is 336 square inches. If the width of a rectangle is 6 inches. What is the length of the rectangle?
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The length of the rectangle is 56

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Which expression is equivalent to (2^3)^-5
Ostrovityanka [42]
Hi!

You didn't list the options, but I think I know the answer. Let me know if my answer isn't listed! :)

(x^{3} )^{-5}
We need to multiply the exponents.
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3 years ago
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0/1 For positive integer n, n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?. What is the value of 4# · 3# · 2# · 1#?
MakcuM [25]

Answer:

331776

Step-by-step explanation:

Since n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?

Then 4# = 4? · (4 − 1)? · (4 − 2)?· 1?

= 4? · 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 4? = 4! · (4 − 1)! · (4 − 2)! · 1! = 4! · 3! · 2! · 1! = 288

Thus, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Also, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 4# = 4? · 3? · 2?· 1? = 288 × 12 × 2 × 1 = 6912

We now find 3#

3# = 3? · (3 − 1)? · 1? = 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Thus, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 3# = 3? · 2?· 1? = 12 × 2 × 1 = 24

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2# = 2? · (2 − 1)? · 1? = 2? · 1?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 2# = 2?· 1? = 2 × 1 = 2

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1# = 1? · 1? = 1? · 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

And, 1# = 1? · 1? = 1 × 1 = 1

So,  4# · 3# · 2# · 1#? =  6912 · 24 · 2 · 1? = 331776

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