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nadya68 [22]
3 years ago
15

Can someone please help me with this?

Mathematics
2 answers:
Gala2k [10]3 years ago
7 0
The first, second, and third one
Lerok [7]3 years ago
6 0
A, B, and C are correct. My bad.
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In a relay race, Nancy ran her part in 15.25 seconds, John ran his part in 13.8 seconds, Sylas ran his part in 16.4 seconds. Wha
sp2606 [1]

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45.45

Step-by-step explanation:

7 0
3 years ago
HELP HELP HELP PLEASE
zepelin [54]

Answer:

integer = 5

rational number but not an integer - 3 and a 1/2

irrational number - it's the one with 11

7 0
3 years ago
|x+11| =−1<br> plz help show steps 2
dezoksy [38]

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No solutions. You can’t have a negative absolute value.

3 0
3 years ago
Someone please help and explain will mark brainliest
Ugo [173]

Answer:

Lee earns 2x.

They both earn 3x.

Step-by-step explanation:

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5 0
2 years ago
Verify that (cos²a) (2 + tan² a) = 2 - sin² a....<br>​
Sveta_85 [38]

Trigonometric Formula's:

\boxed{\sf \ \sf \sin^2 \theta + \cos^2 \theta = 1}

\boxed{ \sf tan\theta = \frac{sin\theta}{cos\theta} }

Given to verify the following:

\bf (cos^2a) (2 + tan^2 a) = 2 - sin^2 a

\texttt{\underline{rewrite the equation}:}

\rightarrow \sf (cos^2a) (2 + \dfrac{sin^2 a}{cos^2 a} )

\texttt{\underline{apply distributive method}:}

\rightarrow \sf 2 (cos^2a) + (\dfrac{sin^2 a}{cos^2 a} ) (cos^2a)

\texttt{\underline{simplify the following}:}

\rightarrow \sf 2cos^2 a  + sin^2 a

\texttt{\underline{rewrite the equation}:}

\rightarrow \sf 2(1 - sin^2a )  + sin^2 a

\texttt{\underline{distribute inside the parenthesis}:}

\rightarrow \sf 2 - 2sin^2a   + sin^2 a

\texttt{\underline{simplify the following}} :

\rightarrow \sf 2 - sin^2a

Hence, verified the trigonometric identity.

7 0
2 years ago
Read 2 more answers
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