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diamong [38]
3 years ago
7

A variable for 7 to the 3rd power

Mathematics
2 answers:
vichka [17]3 years ago
6 0

It’s 7x7x7 because it’s to the 3rd power so 7x7x7 is to the third power so it would not be 7x3.

Answer- 7x7x7

topjm [15]3 years ago
3 0

7x7x7, I think so not entirely sure. But 7³ is 7x7x7 it's not 7x3

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1.5.3
SIZIF [17.4K]

Answer:

A. x^2 = (4x - 1)^2 + (6x + 7)^2

Step-by-step explanation:

The question seems to be incomplete. However, we'll make the following assumption.

Opposite = 6x + 7

Adjacent = 4x - 1

Hypothenuse = x

Pythagoras theorem states that:

Hypothenuse^2 = Opposite^2 + Adjacent^2

Substitute values for Hypothenuse, Opposite and Adjacent.

This gives

x^2 = (6x + 7)^2 + (4x - 1)^2

or

x^2 = (4x - 1)^2 + (6x + 7)^2

From the list of given options.

A answers the question

5 0
3 years ago
What is the perimeter?
LenKa [72]

Answer:

41.13m

Step-by-step explanation:

the circumference of the circle is 25.13 and the 8 on both sides equals to 16

8 0
3 years ago
Visitors to a carnival can buy an unlimited-ride pass for 50$ or an entrance-only pass for 20$. In one day, 282 passss were sold
olchik [2.2K]
20*282= 5640
10680-5640=5040
50-20=30
5040 dividend by 30= 168
Answer: 168
6 0
3 years ago
Please help me
kirza4 [7]
This is a hexagonal prism: Volume = Area of Base (hexagon) x Height:
There are 6 equal equilateral triangles in a hexagone.
The apothem (or altitude of each triangle) = side x (√3)/2 =12(√3)/2 = 6√3
Area of ONE equilateral triangle = (side x altitude)/2:
Area of ONE equilateral triangle = (12 x 6√3)/2 = 36√3 ft²
Area of the SIX equilateral triangles = 36√3 x 6 = 216√3 ft²
VOLUME = BASE X HEIGHT = 216√3 x 15 = 3240√3 ft³

OR VOLUME = 5612 ft³

6 0
3 years ago
Show all work to factor x4 − 10x2 + 9 completely.
leva [86]

Answer:

(x+1)(x-1)(x+3)(x-3)

Step-by-step explanation:

x4-10x^2+9

Group expression so that the coefficients of the x^2 terms add up to +9.

= x^4 -9x^2   - x^2+9

match coefficients in both groups

= x^4 -9x^2   - (x^2-9)

factor each group

= x^2 (x^2-9) - 1(x^2-9)

now factor out the common factor (x^2-9)

= (x^2-1)(x^2-9)

Finally, factor each quadratic factor

= (x+1)(x-1)(x+3)(x-3)

6 0
3 years ago
Read 2 more answers
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