Im thinking its c, not sure
1 answer:
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In this case we can make a proportion.
Now cross multiply.
9600 = 75x
Divide both sides by 75.
X=128
He will make 128 jokes in 1200 mins.
Now cross multiply.
9600 = 75x
Divide both sides by 75.
X=128
He will make 128 jokes in 1200 mins.
Answer:
B. 650 Roast Beef, 490 Tuna, 900 Turkey
Step-by-step explanation:
As this chart displays the order that occured in one week, in order to find the estimate for the month is to multiply the values on the chart by how many weeks there are in a month.
As there are 4 weeks in a months, we can multiply each value by this ratio
Roast Beef:
Tuna:
Turkey:
As this is an estimate, we are looking for the option that is the closest to these estimated values.
Option B is the closest to these values.
Answer:
60.26% probability that less than twenty students are absent
Step-by-step explanation:
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
The standard deviation of the binomial distribution is:
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that ,
.
In this problem, we have that:
.
So
If a random sample of 120 names is called on a Monday, what is the probability that less than twenty students are absent?
This is the pvalue of Z when X = 20-1 = 19. So
has a pvalue of 0.6026.
60.26% probability that less than twenty students are absent