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DanielleElmas [232]
3 years ago
6

Plz guys help me I don't no how to do math plz

Mathematics
1 answer:
zaharov [31]3 years ago
6 0
The image does not load, some "enter your password" thing pops out. idk?
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How can you tell if 2 functions are inverses of eachother
HACTEHA [7]

Remember, if the two graphs are symmetric with respect to the line y = x (mirror images over y = x ), then they are inverse functions. But, we need a way to check without the graphs, because we won't always know what the graphs look like! then f(x) and g(x) are inverse functions.
7 0
3 years ago
Prudie needs $90 or more to be able to take her family out to dinner. She has already saved $30 and wants to take her family out
Aleks [24]
90≤4x+30

Yes she will have enough. 4 multiplied by 18 is 72. 72+30=102. 

Hope this helped.
7 0
2 years ago
For Tran Please help is appreciate it
Ostrovityanka [42]

Answer:

A = 38°

Step-by-step explanation:

We are going to use cosine law to find angle A where

a = 4.7

b = 3.9 m

c = 2.9 m

{c}^{2}  =  {a}^{2}  +  {b}^{2}  - 2ab \cos(  \alpha )

or

\cos( \alpha  )  =  \frac{ {a}^{2}  +  {b}^{2} -  {c}^{2}  }{2ab}

cos A = [(4.7)^2 + (3.9)^2 - (2.9)^2]/2(4.7)(3.9)

= 28.89/36.66

= 0.788

A = arccos(0.788) = 38°

6 0
2 years ago
Solve for s.<br><br><br><br> 5/9s+13/9s=24
aleksley [76]
Start by combining like terms: 
( \frac{5}{9} s + \frac{13}{9}s)=24&#10;
\frac{5}{9} s + \frac{13}{9}s=2s

Now we have:
2s=24

Divide both sides by 2 to isolate s

\frac{2s}{2} = \frac{24}{2}

Final answer:

s=12
3 0
2 years ago
Someone help me please
AlladinOne [14]
To find the equation of a line, you need to find the slope and y-intercept by using the slope formula and point slope formula. 

First, let's find the slope. 11 + 5/9 - 1 = 16/8 = 2. Therefore, the slope is 2.

Then, plug it into the point slope formula. 
y + 5 = 2(x - 1). 
Distribute: y + 5 = 2x - 2

Subtract 5 on both sides: y = 2x - 7. 

Your final equation, that you need to plug into your answer, is y = 2x - 7.

Hope this helps!! If you need further assistance, message me or comment under this post!
7 0
3 years ago
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