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7nadin3 [17]
3 years ago
10

How much candy at $1.20 a pound should be mixed with candy worth 95¢ a pound in order to obtain a mixture of 50 pounds of candy

worth a dollar a pound?
Mathematics
1 answer:
Nesterboy [21]3 years ago
5 0

10 pounds of candy costing $1.20 per pounds must be mixed with 40 pounds of candy costing $ 0.95 per pound to obtain a 50 pounds of candy costing $ 1 per pound

<em><u>Solution:</u></em>

Let "x" be the pounds of candy at $ 1.20 per pound

Then (50 - x) is the pounds of candy at $ 0.95 per pound ( since 95 cents is equal to 0.95 pound)

Therefore, x pounds of candy costing $1.20 per pounds must be mixed with (50 - x)  pounds of candy costing $ 0.95 per pound to obtain a 50 pounds of candy costing $ 1 per pound

Then the equation becomes,

1.20x + (50 - x)0.95 = 50 x 1

On expanding we get,

1.20x + 47.5 - 0.95x = 50

0.25x = 50 - 47.5

0.25x = 2.5

x = 10

Then (50 - x) = 50 - 10 = 40

So we need 10 pounds of candy worth $ 1.20 per pound and 40 pounds of candy worth $ 0.95 to obtain 50 pounds of candy worth a dollar a pound

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