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2 years ago

Need help for this Algebra question plz!

Mathematics

1 answer:

Vikentia [17]2 years ago

5 0

Answer:

2x+5y=-15

ax+bx=c

slope=-a/b so -2/5 matches up with point slope form

then to get y intercept substitite x in point slope for 0 and solve for Y to get -3

then do c/b to get y intercept, so -15/5, which equals -3.

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pentagon [3]

Answer:

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Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is 0)
Parallel lines always have the same slope

1) Determine the slope (m)

$y=\frac{5}{2}x-10$

In the given equation, $\frac{5}{2}$ is in the place of m, making it the slope. Because parallel lines have the same slope, the line we're currently solving for therefore has a slope of $\frac{5}{2}$ . Plug this into $y=mx+b$ :

$y=\frac{5}{2}x+b$

2) Determine the y-intercept (b)

$y=\frac{5}{2}x+b$

Plug in the given point (-6,-29) and solve for b

$-29=\frac{5}{2}(-6)+b$

Simplify -6 and 2

$-29=\frac{5}{1}(-3)+b\\-29=(5)}(-3)+b\\-29=-15+b$

Add 15 to both sides to isolate b

$-29+15=-15+b+15\\-14=b$

Therefore, the y-intercept is -14. Plug this back into $y=\frac{5}{2}x+b$ :

$y=\frac{5}{2}x-14$

I hope this helps!

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