Answer:
ferris wheel travel approx = 434.72 ft
Step-by-step explanation:
given data
wheel rotates = 9pi/8 radians
total height of the ferris wheel = 246 ft
solution
we can say here that height of the ferris wheel is same as the diameter of the wheel
and wheel is circular in shape
so we get here first radius of wheel that is
radius = half of diameter ..........................1
put here value and we get
radius = 0.5 × 246
radius = 123 ft
and
wheel travel distance = length of arc by a angle of wheel rotates
so here length of arc will be
arc length = radius × wheel rotates angle .....................2
put here value and we get
arc length = 123 ×
arc length = 434.7178 ft
so ferris wheel travel approx = 434.72 ft
Answer:
554
Step-by-step explanation:
add 504 plus 10% and you get 554.
Step-by-step explanation:
5 + d > 5 - d
5 + d + d > 5
5 + 2d > 5
2d > 5 - 5
2d > 0
d > 0 ÷ 2
d > 0
Answer:
- ∠ROK = 36°
- ∠CKO = 96°
- ∠C = 60°
Step-by-step explanation:
The same-side angles at each base are supplementary, so ...
∠ROC = 180° -120° = 60°
Because the trapezoid is isosceles, 60° also the measure of ∠C.
The angle sum theorem tells you ...
∠COK +∠ROK = ∠ROC
24° + ∠ROK = 60°
∠ROK = 36° . . . . . . subtract 24°
__
The sum of angles in ΔCKO is 180°, so ...
∠C +∠COK +∠CKO = 180°
60° +24° +∠CKO = 180°
∠CKO = 96° . . . . . . . . . . . . . subtract 84°