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3 years ago

Solve for x.solve for x

Mathematics

1 answer:

LekaFEV [45]3 years ago

3 0

Answer:

The answer to your question is the letter D.

Step-by-step explanation:

Equation

(x + 5)/(x² + 7x + 10) = (x - 4)/ (x² - 2x - 8)

Process

1.- Factor both denominators

x² + 7x + 10 = (x + 5)(x + 2)

x² - 2x - 8 = (x - 4)(x + 2)

2.- Substitute

(x + 5) / (x + 5)(x + 2) = (x - 4)/(x - 4)(x - 2)

3.- Simplify

1/(x + 2) = 1/(x - 2)

4.- Solve for x (cross multiplication)

x - 2 = x + 2

x - x = 2 + 2

0 = 4

5.- Conclusion

The solution is all real numbers except -5, -2 and 4.

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Find the volume of the composite solid. Round your answer to the nearest tenth.

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3 years ago

Read 2 more answers

What is the first term in the sequence for which d = -2 and a7 = 3?

lana66690 [7]

Answer:

First term is 15

Step-by-step explanation:

Given data:

$a_{7} =3\\d=-2$

Now,

$a+6d=3.....(1)\\a_{n} =a+(n-1)d\\\\\\From equation (1)\\a+6(-2)=3\\a-12=3\\a=12+3\\a=15$

Therefore first term a =15

Correct option is (c)

7 0

3 years ago

Evaluate the following when a= 1 ,b=3,and c =27 ( a) 6a^2+ 2bc-2c^1/3

Dennis_Churaev [7]

Answer:

6a^2+ 2bc-2c^1/3 <u>= 162</u>

Step-by-step explanation:

a = 1
b = 3
c = 27

$\rm 6 {a}^{2} + 2bc - 2 {c}^{ \frac{1}{3} }$

$= 6 {(1)}^{2} + 2(3)(27) - 2( {27)}^{ \frac{1}{3} }$

$\rm = 6 + 162 - 2 ( \sqrt[3]{27} )$

$\rm = 168 - 2(3)$

$\rm = 168 - 6$

$\boxed{\rm = 162}$

5 0

3 years ago

Solve algebraically: x2 − x ≥ 6.

hammer [34]

Answer:

B. x ≥ 3 or x ≤ −2

Step-by-step explanation:

<u>Inequalities</u>

Solve the inequality:

$x^2-x\ge 6$

Subtracting 6:

$x^2-x-6\ge 0$

Factoring:

(x-3)(x+2) ≥ 0

We have a product that must be greater or equal to 0. This can only happen if:

x - 3 ≥ 0 and x + 2 ≥ 0

Or:

x - 3 ≤ 0 and x + 2 ≤ 0

The first couple of conditions yields to:

x ≥ 3 and x ≥ -2

Which lead to the solution

x ≥ 3 [1]

The second couple of conditions yields to:

x ≤ 3 and x ≤ -2

Which lead to the solution

x ≤ -2 [2]

The final solution is [1] or [2]:

Answer:

B. x ≥ 3 or x ≤ −2

5 0

3 years ago