Question

Evaluate the following when a= 1 ,b=3,and c =27 ( a) 6a^2+ 2bc-2c^1/3​

Answer 1

Answer:

6a^2+ 2bc-2c^1/3 = 162

Step-by-step explanation:

• a = 1
• b = 3
• c = 27

$\rm 6 {a}^{2} + 2bc - 2 {c}^{ \frac{1}{3} }$

$= 6 {(1)}^{2} + 2(3)(27) - 2( {27)}^{ \frac{1}{3} }$

$\rm = 6 + 162 - 2 ( \sqrt[3]{27} )$

$\rm = 168 - 2(3)$

$\rm = 168 - 6$

$\boxed{\rm = 162}$