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oksian1 [2.3K]
4 years ago
7

Find the domain of the given function f(x) =

Mathematics
1 answer:
asambeis [7]4 years ago
7 0

Assuming imaginary numbers aren't possible the answer would be

x < -3

otherwise

x not= -8 and 2

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Describe the difference between solving |x| ≤ 5 and solving |x| ≥ 5.
11Alexandr11 [23.1K]
|x| is greater then 5 on |X|>5 and the other x is lees then 5 on |X|<5
8 0
3 years ago
The circumference of a circle is 28 pi meters. What is its radius
astraxan [27]

Circumference's formula is: 2πr

Since π is not added in the total (as it is 28π), just divide 28 with 2 to get r

28/2 = 14

The radius is 14

hope this helps

6 0
3 years ago
Read 2 more answers
30/root 3-3 root 5<br> Ple answer this question
adoni [48]

\frac{30}{ \sqrt{3} - 3 \sqrt{5} } \\ \\ =\frac{30}{ \sqrt{3} - 3 \sqrt{5} } \times \frac{\sqrt{3} + 3 \sqrt{5}}{\sqrt{3} + 3 \sqrt{5}} \: \\ \\ that \: simply \: means \: multiplying \: by \: 1 \\ \\ \frac{30(\sqrt{3} + 3 \sqrt{5})}{ (\sqrt{3} + 3 \sqrt{5}) (\sqrt{3} - 3 \sqrt{5}) } \: \: \\ \\ by \: using \: formula \: {a}^{2} - {b}^{2} \\ \\ we \: get \\ \\ = \frac{30 \sqrt{3} + 90 \sqrt{5} }{ 3 - 45} \\ \\ = -  \frac{30( \sqrt{3} + 3 \sqrt{5}) }{42} \\ \\ =  - \frac{10( \sqrt{3} + 3 \sqrt{5}) }{14} \:  \:

4 0
3 years ago
5a²b² ×(3a²-4ab+6b²)​
slega [8]

Answer:

15a⁴b²-20a³b³+30a²b⁴

Step-by-step explanation:

3a²-4ab+6b²

so for 5a²b²

(5a²b²)(3a²-4ab+6b²)

=15a⁴b²-20a³b³+30a²b⁴

3 0
3 years ago
What value is the 4 in number 358.547
TiliK225 [7]

Answer:

Hundredths place

Step-by-step explanation:

3 is hundred

5 is ten

8 is ones

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5 is tenths

4 is hundredths

7 is thousandths

3 0
3 years ago
Read 2 more answers
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