If the four lines are extended, which system would have only one solution?

1 answer:

xeze [42]4 years ago

7 0

Answer:

A line a and line b

Step-by-step explanation:

Lines b and c are parallel (no intersection points), so the system will have no solutions.

Lines b and d are parallel (no intersection points), so the system will have no solutions.

Lines c and d coincide (infinitely many intersection points), so the system will have infinitely many solutions.

Lines a and b will intersect after extension, so the system of these two equations will have only one solution.

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Setler79 [48]

I think that would be 98000c^2m^4-83cm

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3 years ago

g100num [7]

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3 years ago

Pachacha [2.7K]

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Ira Lisetskai [31]

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3 years ago

denpristay [2]

Answer: No. Jamies reasoning doesn't make any sense.

Counter example :- Isha decides to go on walk on every 4th day and go for gym on every 2nd day in a month.

Then Isha will do both the things on same day = LCM (4,2)

Now, LCM of 4 and 2 = 4

Therefore, Isha will do both the things on 4th day of the month .

Step-by-step explanation:

Jamies reasoning doesn't make any sense.

Because the LCM of 3 and 6 = 6 not 18[since 6=3×2]

LCM is the least common multiple number of two or more numbers.

7 0

4 years ago