1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zigmanuir [339]
3 years ago
14

Help please!! 5th grade math.

Mathematics
2 answers:
sergey [27]3 years ago
6 0

Answer:

2 1/3

Step-by-step explanation:

PolarNik [594]3 years ago
3 0

mixed number is 2 1/3

You might be interested in
For what real values of does the quadratic 12x^2+k*x+27=0 have nonreal roots
icang [17]

Step-by-step explanation:

Discriminant : k² - 4(12)(27) < 0

So k² - 1296 < 0, -36 < k < 36.

3 0
3 years ago
Read 2 more answers
Can you help me find my mistake
Hunter-Best [27]
Sorry i dont know im not that far in school that's like high school stuff sorry


8 0
3 years ago
2/3x + 1/6 = -3/4x + 1
kupik [55]
\frac{2}{3} x +  \frac{1}{6}  =  -\frac{3}{4} x + 1

First, simplify \frac{2}{3} x to \frac{2x}{3} / Your problem should look like: \frac{2x}{3} +  \frac{1}{6} =  -\frac{3}{4} x + 1
Second, simplify \frac{3}{4} x to \frac{3x}{4} / Your problem should look like: \frac{2x}{3} +  \frac{1}{6} =  -\frac{3x}{4} + 1
Third, multiply both sides by 12 (the LCM of 3 and 4) / Your problem should look like: 8x + 2 = -9x + 12
Fourth, subtract 2 from both sides. / Your problem should look like: 8x = -9x + 12 - 2
Fifth, simplify -9x + 12 - 2 to -9x + 10. / Your problem should look like: 8x = -9x + 10
Sixth, add 9x to both sides. / Your problem should look like: 8x + 9x = 10
Seventh, add 8x + 9x to get 17x. / Your problem should look like: 17x = 10
Eighth, divide both sides by 17. / Your problem should look like: x =  \frac{10}{17}

Answer as fraction: x = \frac{10}{17}
Answer as decimal: x = 0.5882

7 0
3 years ago
There are four movies showing at the theater, 2/5 of the people bought tickets for the comedy, 1/4 bought tickets for the horror
RUDIKE [14]

Given:

Number of people bought tickets for comedy = \frac{2}{5}

Number of people bought tickets for horror = \frac{1}{4}

Number of people bought tickets for kids movie = \frac{3}{10}

To find the number of people who bought tickets for the action movie.

Let us take,

Total number of tickets = 1

Now,

Total number of tickets for comedy, horror and kids movie are = (\frac{2}{5} +\frac{1}{4} +\frac{3}{10} )

So,

(\frac{2}{5} +\frac{1}{4} +\frac{3}{10} )

LCM of 5,4,10 = 20

= \frac{8+5+6}{20}

= \frac{19}{20}

Rest are action movie's tickets.

Therefore,

Number of action movie tickets = 1-\frac{19}{20}

= \frac{20-19}{20}

= \frac{1}{20}

Hence,

The number of people who bought the tickets for action movie is \frac{1}{20}.

7 0
4 years ago
Which triangle must be a right triangle and why?
Lapatulllka [165]
Of your answers, the first one is correct. There are two right triangles in the graph, ABC and A'B'C'. However, only A'B'C' is listed.
8 0
3 years ago
Read 2 more answers
Other questions:
  • What is the answer for r+11+8r=29
    12·1 answer
  • In Wellington, a city of 360,000 citizens, there has been an outbreak of vampires and werewolves There are 3,000 people infected
    8·1 answer
  • Carol Byrd gets a student rate of $30.00 a month. There is a $250 deductible; but no coinsurance payment. She recently received
    9·2 answers
  • I need help please help
    9·1 answer
  • What does it mean for a product of factors to be expressed using component?
    5·1 answer
  • Plz show work and help me
    14·2 answers
  • Pleaseeeee answer correctly !!!!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!
    11·1 answer
  • Please help ASAP. I really need this it is almost due. Please give me the right answer.
    15·1 answer
  • Solve the system of equations.<br> 2x-6y=8<br> x-3y=9<br><br> Plz help I’m superrr confused
    13·1 answer
  • Christian reads 1/4 of a book every 2/3 weeks how many books does Christain read per week​
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!