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3 years ago

Can you guys please answer this thank you

Mathematics

1 answer:

11111nata11111 [884]3 years ago

3 0

Answer:F B G E A

Step-by-step explanation:

1. F( a rigid transformation only changes the position but the size and angles remain the same)

2. B(The angle of rotation symmetry is the smallest angle the figure can be rotated to coincide with itself.)

3. G(Congruent means that it is the same size and shape)

4. E(Translation moves the whole shape including the points so that the shape and sizes remain the same)

5. A(Though it's position may change, reflective symmetry ensures that no other parts of the shape can change no matter what.)

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Let y=f(x)=(3x+7)/(x-2) <br> find a rule for f^-1

Murrr4er [49]

Answer:

$f^{-1}(x)=\frac{2x+7}{x-3}$ .

Step-by-step explanation:

The given function is $f(x)=\frac{3x+7}{x-2},\:x\ne2$ .

We want to find a rule for $f^{-1}(x)$ .

Let $y=\frac{3x+7}{x-2}$ .

Interchange x and y.

$x=\frac{3y+7}{y-2}$ .

Solve for y.

$x(y-2)=3y+7$ .

Expand

$xy-2x=3y+7$ .

Group y-terms

$xy-3y=7+2x$ .

Factor

$(x-3)y=7+2x$ .

$y=\frac{2x+7}{x-3}$ .

$\therefore f^{-1}(x)=\frac{2x+7}{x-3},\:x\ne3$ .

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3 years ago

(9w x 0) - 12 and 9w - 12<br><br> Is it equivalent or not

Natalija [7]

It is not. 9w x 0 is 0, then 0-12 is -12.

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3 years ago

un rectangulo tiene 28 cm de perimetro y unos de sus lados mide 4 cm ¿cuantos cuadrados de 2 cm por lado se mecesitan para armar

seraphim [82]

Answer:

10 cuadrados

Step-by-step explanation:

Si uno de los lados de rectangulo es de 4cm entonces el lado parallelo tambien es de 4cm. Eso nos da 8cm del perimetro y nos quedan los otros dos lados que tienen la misma medida. Entonces dividimos el resto del perimetro por 2.

28 - 8 = 20cm

20cm / 2cm = 10cm

Ahora que tenemos todas las medidas podemos multiplicar el largo por el ancho para calcular el area del rectangulo

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el cuadrado de 2cm tendra un area de

2cm * 2cm = 4 $cm^{2}$

Ahora simplemente dividimos el area del rectangulo por el area del cuadrado para saber cuantos cuadrados necesitamos para armar ese rectangulo

40 $cm^{2}$ / 4 $cm^{2}$ = 10 cuadrados

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