Answer:
3 = x
Step-by-step explanation:
0 > 3x - 3 - 6
You want to group up the -3 and -6 first
0 > 3x - 9
Then you want to add 9 to each side to cancel out the negative 9 on one side.
0 > 3x - 9
+9 +9
9 > 3x
Now you just divide by 3 on each side
3 = x
Answer:
R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Step-by-step explanation:
Squaring both sides of equation:
I^2 = (ER)^2/(R^2 + (WL)^2)
<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)
<=>(ER)^2 - (IR)^2 = (IWL)^2
<=> R^2(E^2 - I^2) = (IWL)^2
<=> R^2 = (IWL)^2/(E^2 - I^2)
<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Hope this helps!
Answer:
C Infinitely Many Solutions
Step-by-step explanation:
i put the 2 equations into Desmos Graphing Calculator and they are the same line so it has infinitely many solutions.
More information is needed to solve the problem.
2300 out of 4500 were chosen
2300 / 4500 = 0.5111
0.51 = 51%
51% is the acceptance rate.
