Question

Someone please help me? I don't know how to solve these :/

Answer 1

$2x^2-x-6=0\\ 2x^2-4x+3x-6=0\\ 2x(x-2)+3(x-2)=0\\ (2x+3)(x-2)=0\\ x=-\frac{3}{2} \vee x=2$

Answer 2

$2x^2 - x - 6 = 0$

$(2x - 3) (x + 2) = 0$

$2x - 3 = 0$

$2x = 3$

$x = \frac{3}{2}$

$x + 2 = 0$

$x = -2$

$x = \frac{3}{2} , 2$