Answer:
Probability that the son will be:
color-blind = 1/2
blue eyed = 1/8
blue eyed and color-blind = 1/16
Explanation:
Mother : BbXcX
Father : BbXY
Colorblindness is X linked recessive trait hence will be caused when the son has XcY genotype.
XcX X XY :
Xc X
X XcX XX
Y XcY XY
Half of the sons will have normal vision and other half will be colorblind hence, there is 1/2 probability that the son will be colorblind.
Eye color is autosomal trait and blue color will be produced when the child has bb genotype.
Bb X Bb :
B b
B BB Bb
b Bb bb
1/4 of the children will have blue eyes. Since half of the children are expected to be males, 1/4 * 1/2 = 1/8 sons are expected to have blue eyes.
Probability of a son being blue eyed and color blind will be :
1/8 * 1/2 = 1/16
C...the key is that they are photosynthetic...so they produce oxygen (like plants)!
Answer:
any use of electricity in the stadium
Explanation:
Answer:
Examples:
- Short-term adaptation: feedback inhibition
- Long-term adaptation: regulation of gene expression
Explanation:
Feedback inhibition is a mechanism where the product of a chemical reaction is utilized to modulate its own subsequent synthesis. In bacteria, feedback inhibition allows regulating different metabolic pathways in response to environmental conditions by modulating enzyme activity through enzyme reaction products. Moreover, bacteria may also respond to environmental inputs by long-term changes in gene expression. For example, bacteria contain transcription factors activated during stress, which are able to activate the transcription of particular genes into messenger RNAs (mRNAs) that would subsequently be used to generate particular enzymes by the process of translation. These transcription factors may bind to specific DNA motifs in order to promote transcriptional activity, thereby regulating the production of the corresponding enzyme.
Answer:
The correct answer is B. The virus can infect the host.
Explanation:
- As the host and the virus both remain in the agar plate, the virus is capable of infecting the host cells.
- The host cell multiplies and grows by utilising the nutrient from the agar medium.
- After the virus particles infect the host, they replicate inside the host and produce new progeny virions which get released out of the host cell by killing it.
- The newly formed virions infect other host cells and the process continues.
- The killing of the host cells by the viruses result in the generation of clear zones on the agar plate which is also known as the zone of exclusion.
- In the zone of exclusion region, the host cells have been killed by the viruses.
