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tresset_1 [31]
2 years ago
6

Graph the solution set. please help

Mathematics
1 answer:
Ratling [72]2 years ago
7 0

Answer:

In the attachment.

Step-by-step explanation:

Rewrite x\geq-3y-6 as a y\geq -\frac{1}{3}x-2. Then mark each set with different color and take the intersection of these.

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What is 679 rounded to the nearest ten
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What is 2/5 ÷ 4/7 equal to
olchik [2.2K]
When you have to divide a fraction, you have to invert the second fraction (4/7 becomes 7/4), and you then multiply the two fractions.

=2/5 ÷ 4/7
=2/5 * 7/4
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Multiply the denominators on bottom
=(2*7)/(5*4)
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3 years ago
Prove the diagonals of a square are perpendicular
zysi [14]

Answer:

Given :- ABCD is a square.

To proof :- AC = BD and AC ⊥ BD

Proof :- In △ ADB and △ BCA

AD = BC [ Sides of a square are equal ]

∠BAD = ∠ABC [ 90° each ]

AB = BA [ Common side ]

△ADB ≅ △BCA [ SAS congruency rule ]

⇒ AC = BD [ Corresponding parts of congruent triangles are equal ]

In △AOB and △AOD

OB = OD [ Square is also a parallelogram therefore, diagonal of parallelogram bisect each other ]

AB = AD [ Sides of a square are equal ]

AO = AO [ Common side ]

△AOB ≅ △ AOD [ SSS congruency rule ]

⇒ ∠AOB = ∠AOD [ Corresponding parts of congruent triangles are equal]

∠AOB + ∠AOD = 180° [ Linear pair ]

∠ AOB = ∠AOD = 90°

⇒ AO ⊥ BD

⇒ AC ⊥ BD

Hence proved, AC = BD and AC ⊥BD

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2. The two figures are similar. Complete sentences
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