3 years ago

Factor 4x^3-400x thanks a lot

Mathematics

1 answer:

mario62 [17]3 years ago

5 0

Answer:

4x(x-10)(x+10)

Step-by-step explanation:

4x^3-400x

Factor out 4x

4x(x^2-100)

We know that x^2-100 is the difference of squares

a^2 - b^2 = (a-b)(a+b)

4x(x^2-100)= 4x(x^2 -10^2)

4x(x-10)(x+10)

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Hey, There 20percntcooler! :)

To solve these equations, we will need to substitute.
$x-y=4$
or
$4+y=x$

We can substitute this for x so, we don't have to deal with two different variables.
$x+2y=4$
or if substituted:
$4+y+2y=4$

Solve for y.
$4+y+2y=4$
Add like terms.
$4+3y=4$
Subtract 4 from both sides.
$(4+3y)-4=(4)-4$
$3y=0$
Divide both sides by 3.
$(3y)/3=(0)/3$
$y=0$

Now lets input the value for y into the equation to find the value of x.
$x-0=4$
Add 0 to both sides.
$(x-0)+0=(4)+0$
$x=4$

$x=4$
$y=0$

Hope this helps.
-Benjamin

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