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3 years ago

32. The length of a rectangle measures six more than the width. The perimeter of the rectangle is 38.

Mathematics

1 answer:

Ne4ueva [31]3 years ago

6 0

Answer: 12.5

You start with the equations "2x +2y=38" and "6+x=y". By adding and subtracting in the second equation, you get "2x +2y=38" and "x-y=-6". When you multiply the second equation by 2, you get "2x-2y=-12."

subtracting the equations "2x +2y=38" and "2x-2y=-12" gets you to "4y=50", where you have to divide two sides by 4 and get "y=12.5"

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Step-by-step explanation:

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3 years ago

Find the fifth term of the binomial expansion. (x2+y5) ^8

OlgaM077 [116]

Answer:

The fifth term of the binomial expansion

$T_{5} = 70 x^{8} y^{20}$

Step-by-step explanation:

Step:1

Given that the binomial expansion

( x² + y⁵ )⁸

we know that

$T_{r+1} = n_{C_{r} } a^{r} x^{n-r}$ ...(i)

Step:2

put r = 4

$T_{4+1} = 8_{c_{4} } (x^{2} )^{4} (y^{5} )^{8-4}$

$T_{5} = 70 x^{8} y^{20}$

Final answer:-

The fifth term of the binomial expansion

$T_{5} = 70 x^{8} y^{20}$

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3 years ago

What is the value of this expression when a = 4, b = -5, and c = -7?

Ganezh [65]

Answer:

The value of the given expression is -878.08.

Step-by-step explanation:

Here, the given question is INCOMPLETE.

The complete question is:

Evaluate the expression for a = 4, b = -5, and c = -7. $4a^2b^{-2}c^3$

Here, substitute the vale of a = 4, b = -5 and c = -7, we get:

$4a^2b^{-2}c^3 = (\frac{4a^2c^3}{b^2}) = (\frac{4(4)^2(-7)^3}{(-5)^2})\\= (\frac{64 \times 343}{25}) =\frac{21,952}{25} = 878.08\\\implies 4a^2b^{-2}c^3 = 878.08 ( a = 4, b = -5 ,c = -7)$

Hence, the value of the given expression is -878.08.

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3 years ago