First of all we need to find a representation of C, so this is shown in the figure below.
So the integral we need to compute is this:

So, as shown in the figure, C = C1 + C2, so:
Computing first integral:
Applying derivative:

Substituting this value into

Computing second integral:
Applying derivative:

Substituting this differential into


We need to know the limits of our integral, so given that the variable we are using in this integral is x, then the limits are the x coordinates of the extreme points of the straight line C2, so:
![I_{2}= -8\int_{4}^{8}}dx=-8[x]\right|_4 ^{8}=-8(8-4) \rightarrow \boxed{I_{2}=-32}](https://tex.z-dn.net/?f=I_%7B2%7D%3D%20-8%5Cint_%7B4%7D%5E%7B8%7D%7Ddx%3D-8%5Bx%5D%5Cright%7C_4%20%5E%7B8%7D%3D-8%288-4%29%20%5Crightarrow%20%5Cboxed%7BI_%7B2%7D%3D-32%7D)
Finally:
The equation of a straight like in the from y – y1 =m(x-x1) where m is the slope of the like and (x1 , y1) are the coordinates of a given point on the line — compare slope intercept form.
Answer:
-5 and -5.5;
-12.5 and 2
Step-by-step explanation:
Two negative addends, can be added together to give -10.5.
For example:
(-5) + (-5.5) = -5 - 5.5 = -10.5
Also, it is possible for one of the addends to be negative while the other is positive, and their sum will give us -10.5.
For example:
The sum of -12.5 and 2 will give us -10.5.
We are adding a positive and a negative number here. As usual, we will subtract the smaller number from the bigger number, while the result will carry the sign of the bigger number, which in this case is negative sign.
Thus:
(-12.5) + (2) = -10.5
The answer to your question is 89