The probability of not surviving a head-on car accident is: 0.903
Step-by-step explanation:
The probabilities of occurrence and non-occurrence of an event add up to one.
If p is the probability that an even will happen and q is the probability that it will not happen
Then
Here,
Probability of surviving = p = 0.097
Probability of not surviving = q = ?
The probability of not surviving a head-on car accident is: 0.903
Keywords: Probability, Inverse
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Answer:
take a picture of it and then put it up
Step-by-step explanation:
and they should give you the answer
Lets x = width
length = x + 4 (4 meters longer than wide)
A = L * W
192 = x ( x +4)
192 = x^2 + 4x
x^2 + 4x - 192 = 0
(x +16)(x-12) = 0
x - 12 = 0, x = 12
x + 16 = 0, x = -16
so width x = 12
length = 12 + 4 = 16 (4 meters longer than wide)
answer. J
16
Well do you know a common factor between 8, 5, and 12, if so it is super simple to find your answer. :)
Answer:
hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to
Answer: v = 5v + 4u + 1.5sin(3t),
Step-by-step explanation:
u" - 5u' - 4u = 1.5sin(3t) where u'(1) = 2.5 u(1) = 1
v represents the "velocity function" i.e v = u'(t)
As v = u'(t)
<em>u' = v</em>
since <em>u' = v </em>
v' = u"
v' = 5u' + 4u + 1.5sin(3t) ( given that u" - 5u' - 4u = 1.5sin(3t) )
= 5v + 4u + 1.5sin(3t) ( noting that v = u' )
so v' = 5v + 4u + 1.5sin(3t)
d/dt ![\left[\begin{array}{ccc}u&\\v&\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Du%26%5C%5Cv%26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%26%5C%5C4%265%26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26%5C%5C1.5sin%283t%29%26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Given that u(1) = 1 and u'(1) = 2.5
since v = u'
v(1) = 2.5
note: the initial value for the vector valued function is given as
![\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Du%281%29%26%5C%5Cv%281%29%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}1\\2.5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C2.5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
