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Nikolay [14]
2 years ago
10

What's the answer to this?

Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
3 0
Since MO bisects LMN, that means that LMO=LMN and LMO+LMN=LMN (since they add up as shown), meaning that 15x-42=x+56. Subtracting x and adding 42 to both sides, we get 14x=98. Next, we divide both sides by 14 to get x=108/14=7. Adding LMO and LMN up, we get 7*15-42+7+56 (plugging 7 in for x)=21+105=126
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Math Help! 62 points for answer(s) Right answers only, and credible reasoning please.
Andrews [41]
Question #1, refers to the graph that appears on the left:

The graph is comprised of 4 segments.
All of the segments are linear.
Segment 'B' is the only one that's rising.

Question #2, also refers to the graph that appears on the left:

As discussed in the answer to Question #1,
interval-B is a segment that's linear and rising.

Question #3:

Keisha runs to Natasha's house, stays there for 15 minutes,
then ... with Natasha ... runs the rest of the way to swim practice.

If the story is graphed, the graph has 3 segments.  Since the slope
of each segment is Keisha's speed during that interval:
-- the middle segment will have no slope, while she sits motionless
at Natasha's house;
-- the 1st and 3rd segments will have positive slopes, while Keisha
is running.

Choice A).  Terrible choice.  It says that at time=0, when Keisha begins
running, she is 5 blocks from home.  Then it says that the line decreases,
as if she runs from there toward her house.  Not a good choice.

Choice B).  Somewhat better, but doesn't fit the story.  This graph
says that she starts from her house, runs at 3 different speeds
until she is 9 blocks away, then immediately turns around and
spends the next hour running back home.  Also not a good choice.

Choice C).  This is it.  If I had not read the story and just saw this graph,
I could see that Keisha started at her house, ran 5 blocks away from in
0.25 hour, stayed at that -place for the next 0.25 hour, then ran to some
place that was 9 blocks from her house in another 0.25 hour, and finally,
stayed there for the next hour.  That's all the information that appears on
this graph, but it certainly matches the story, and additionally tells us
how long she stayed at swim practice.

Choice D).  Now that we know we have a good graph in choice-C,
this one is not only wildly wrong, but it's funny too.
This graph says that at time zero, Keisha is 5 blocks away from her
house, and she stays right there for 0.3 hour.  She moves 1 block
from there in the next 0.2 hour, then stays at THAT place for the next
0.3 hour, and finally proceeds steadily to 9 blocks from her house
over the next 0.95 hour.

Question #4.    Refers to the graph on the right side.     

This graph is comprised of 5 linear segments.  The slope of
each segment is the rate at which the level of water in the tub
is changing.  A rising line says that the water level is rising.
A falling line says that the water level is falling.  If the water
level isn't changing, then the slope of the line is zero ... it's
a horizontal segment.

Before we even look at the story, let's look at the graph:

Segment A:  the tub is empty at time zero, then rises slowly
                       for about 8 minutes;
Segment B:  suddenly at 8 minutes, the level rises by 50%
                       (from level 20 to level 30) in 2 minutes or less;
Segment C:  for the next 15 minutes, the level doesn't change;
Segment D:  the water drops quickly to level-20 in 2 minutes or less;
Segment E:  in about 8 minutes, the water level drops slowly to zero.

If somebody told us that this was the graph of a girl taking a bath,
we could just about read the story from the graph:
A:  filling the tub from the faucets ... takes 8 minutes;
B:  the person slowly and carefully getting into the tub, making the level rise
C:  the person in the tub;
D:  the person slowly and carefully getting out of the tub;
E:  the tub emptying in 8 minutes.

Now I'm ready to look at the choices.

OK.  I see that the question is only asking about segment-C.

K ran water to fill the tub ... No.  The level isn't changing.
K emptied the tub ... No.  The level isn't changing.
K got into the tub ... No.  The level isn't changing.
K soaked in the bathtub ... Yes !  The level isn't changing.
8 0
3 years ago
Read 2 more answers
Solve (1/8)^-3a=512^3a
lukranit [14]
Solve (1/8)^-3a = 512^3a
A=0

I took the assignment it’s right.
5 0
3 years ago
Read 2 more answers
What is 90 decreased by 40%?
vaieri [72.5K]
Because it's decreasing, you use the formula (1-x/100)y with x the percentage decreased which is here 40, and y the number decreased which is here 90
So we get
(1-40/100) * 90
(100/100 - 40/100) * 90
60/100 * 90 
5400/100
54 
So 90 decreased by 40% is 54
Hope this Helps :)
8 0
3 years ago
If the probability of an event is 0.7 repeating​, what are the odds against the​ event
ivann1987 [24]
So the probability is the number of favorable outcomes divided by the number of total outcomes. This means that the favorable outcomes are 7/9, and the unfavorable outcomes are 2/9. The odds against the event are the unfavorable outcomes. Therefore the odds against the event is 2/9, or 0.2 repeating. Hope this helps. Feel free to ask more questions, and feel free to ask questions about my explanation.
7 0
2 years ago
A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?
professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let x\cdot y = 18, we get an additional equation by implicit differentiation:

x\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0 (1)

From the first equation we find that:

x = \frac{18}{y} (2)

By applying (2) in (1), we get the resulting expression:

\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0 (3)

y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}

\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}

If we know that y = 6 and \frac{dy}{dt} = 8, then the first derivative of x in time is:

\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)

\frac{dx}{dt} = -4

From (1) we determine the value of x at this instant:

x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}

x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)

x = -6\cdot \left(\frac{-4}{8} \right)

x = 3

The value of x at this instant is 3.

4 0
2 years ago
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