Let's see what's the domain and range for the given function ~
![\qquad \tt \dashrightarrow \:domain \in [ -5 , 4 ]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3Adomain%20%5Cin%20%5B%20-5%20%2C%204%20%5D%20)
or
Because domain = all values of x between its maximum (4) and minimum (-5) value [ including them ]
![\qquad \tt \dashrightarrow \:range \in[ -4 , 9 ]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3Arange%20%5Cin%5B%20-4%20%2C%209%20%5D)
or
Because range = all values of y between its maximum (9) and minimum (-4) value [ including them ]
Answer:
Step-by-step explanation:
The domain represents the x-values
The range represents the y-values
Domain Range
3 7
8
-2
4
1
This relation is not a function because the domain value was used more than one time.
Answer:
on the outside of the bracket. The divisor is the number you're dividing by.Set up the division problem with the long division symbol or the the dividend, on the inside of the bracket. The dividend is the number you're dut 32, the divisor, on the outside of the bracket. The divisor is the number you're dividing by.Set up the division problem with the long division symbol or the long division brackPut 487, the dividend, on the inside of the bracket. The dividend is the number yoPut 32, the divisor, on the outside of the bracket. The divisor is the number you're dividing by.
Step-by-step explanation:
Answer:
4 to the second power = 16. that leaves us with 16 - 2 ( 3 x 5 + 1). next, multiply 3 x 5 = 15. that leaves us with 16 - 2 ( 15 + 1 ). next, add 15 + 1 = 16. that leaves us with 16 - 2 ( 16 ). next, multiply 2 ( 16 ) = 32. finally, subtract 16 - 32 = -16
Step-by-step explanation:
your answer is -16. hope this helps
Step-by-step explanation:
Use Eucild division lemma to help solve this.
