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Katena32 [7]
3 years ago
15

How do u do punnet squares

Biology
2 answers:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

SO basically a punnet square is a box into 4 parts

Lets say your given heterozygous dominat and heteroygous

recessive .

You would put the "genes" on the left and top:

when  solving you need to Rr together RR together and rr together.

Readme [11.4K]3 years ago
3 0

Answer:

    X.     X

x/. Xx     / Xx

--------------------

x/ Xx        / Xx

Explanation:

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Question 10
stich3 [128]

Answer:

<h2>Its true!!</h2>

Explanation:

Actually the haemoglobin molecule consists of 2 parts, the haem which is a prosthetic group and the other globin which is a protein. So the haemoglobin as is a protein so, is arranged in quaternary structure of protein which contains 4 subunits. The subunits depend upon the organism whose haemoglobin is being talked about. So the normal haemoglobin found in red blood cells contains 2 alpha subunits + 2 beta subunits. At the centre of each subunit there is the haem part attached. To the centre of haem the Fe3+ ion are present which actually attaches to 1 Oxygen molecule. So as 4 subunits are present and each subunit has 1 Fe3+ ion, so total 4 Oxygen molecules can bind to the 1 Hb molecule!!

4 0
3 years ago
Which of the following scenarios would be an example of diffusion
Brums [2.3K]

i would say the best answer is d

6 0
3 years ago
Que caracteristicas comparten todas las celulas eucariotas ?
Olenka [21]

Explanation:

Las células eucariotas son muy diversas en forma, forma y función. Sin embargo, algunas características internas y externas son comunes a todos. Estos incluyen una membrana plasmática (celular), un núcleo, mitocondrias, orgánulos unidos a la membrana interna y un citoesqueleto.

4 0
3 years ago
Genes A and B are 10 map units apart and genes B and C are 20 map units apart, with gene B located between genes A and C. What w
Marizza181 [45]

Answer:

2% of the progeny will be double crossovers for the trihybrid test cross

Explanation:  

By knowing the positions of genes, we can estimate the distances in MU between them per region.

  • Genes A and B are 10 map units apart (Region I)
  • Genes B and C are 20 map units apart (Region II)
  • Genes A and C are 30 map units apart

----A-------10MU--------B-------------20MU-------------C---

             Region I                      Region II  

We can estimate the recombination frequencies by dividing each distance by 100.

• recombination frequency of A-B region = 10MU / 100 = 0.10

• recombination frequency of B-C region = 20MU / 100 = 0.20

Now that we know the recombination frequencies in each region, we can calculate the expected double recombinant frequency, EDRF, like this:

EDRF = recombination frequency in region I x recombination frequency in region II.

EDRF = 0.10 x 0.20 = 0.02        

2% of the progeny will be double crossovers for the trihybrid test cross

   

7 0
3 years ago
Theory 1 what caused the giraffe neck to become longer
mash [69]
Fossils are found of giraffes with short necks.
Lamarck believed the giraffes stretched their necks and passed it to their offspring
necks grew longer due to stretching.
giraffes need long necks for food and evolution provided it to them
4 0
3 years ago
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