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Pani-rosa [81]
3 years ago
15

A customer survey asked respondents to indicate their highest levels of education. The only three choices in the survey were hig

h school, college, and other. If 26% indicated high school and 47% indicated college, determine the percentage of respondents that chose the “other” category
Computers and Technology
1 answer:
solong [7]3 years ago
4 0

Answer:

27%

Explanation:

100% = 26% + 47% + x%

100% = 73% + x%

27% = x%

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Company WAP has SSID broadcast disable

Explanation:

Disabling SSID broadcast will make your WLAN network name invisible to other users. However, this only hides the name, not the network itself. that's why the user cannot find the company WLAN on her computer but yet can connected to the company WLAN and can browse to multiple websites with no problem from their company-assigned laptops.

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The capacity of a communication channel is measured in _______.
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<span>The capacity of a communication channel is measured in gb and gps.</span>
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You have spent $4,000 on liquor for your bar. Your bar sales have been $24,000. What is your cost of sales for liquor, expressed
amid [387]

Answer:

17%

Explanation:

Given parameters:

Cost price of liquor = $4000

Total sale = $24000

Unknown:

Percentage cost of sale for liquor = ?

Solution:

To find the percentage cost of sale;

       %Cost of sale of liquor = \frac{cost price of liquor}{Total cost of sale }   x 100

Input the variables;

       %Cost of sale of liquor = \frac{4000}{24000}  x 100 = 16.67% = 17%

8 0
3 years ago
Write code to take a String input from the user, then print the first and last letters of the string on one line. Sample run: En
Ainat [17]
<h2>Answer:</h2>

//import the Scanner class to allow for user input

import java.util.Scanner;

//Begin class definition

public class FirstAndLast{

   //Begin the main method

    public static void main(String []args){

       

       

       //****create an object of the Scanner class.

       //Call the object 'input' to receive user's input

       //from the console.

       Scanner input = new Scanner(System.in);

       

       //****create a prompt to tell the user what to do.

       System.out.println("Enter the string");

       

       //****receive the user's input

       //And store it in a String variable called 'str'

       String str =  input.next();

       

       //****get and print the first character.

       //substring(0, 1) - means get all the characters starting

       //from the lower bound (index 0) up to, but not including the upper

       //bound(index 1).

       //That technically means the first character.

       System.out.print(str.substring(0,1));

       

       //****get and print the last character

       //1. str.length() will return the number of character in the string 'str'.

       //This is also the length of the string

       //2. substring(str.length() - 1) - means get all the characters starting

       // from index that is one less than the length of the string to the last

       // index (since an upper bound is not specified).

       // This technically means the last character.

       System.out.print(str.substring(str.length()-1));

       

       

       

    }  // end of main method

   

} //end of class definition

<h2>Explanation:</h2>

The code has been written in Java and it contains comments explaining important parts of the code. Kindly go through the comments.

The source code and a sample output have also been attached to this response.

To run this program, copy the code in the source code inside a Java IDE or editor and save it as FirstAndLast.java

Download java
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
4c53f66d970acf88b251b2cf41bcdaf6.png
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The CPU is the working principle
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