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Svet_ta [14]
3 years ago
7

X = 1 if (A = 1 OR B = 1) OR (A = 0 AND B = 1

Computers and Technology
1 answer:
Gnoma [55]3 years ago
4 0

Answer:

For question a, it simplifies.  If you re-express it in boolean algebra, you get:

(a + b) + (!a + b)

= a + !a + b

= b

So you can simplify that circuit to just:

x = 1 if b = 1

(edit: or rather, x = b)

For question b, let's try it:

(!a!b)(!b + c)

= !a!b + !a!bc

= !a!b(1 + c)

= !a!b

So that one can be simplified to

a = 0 and b = 0

I have no good means of drawing them here, but hopefully the simplification helped!

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Hit and Slopes Program: A Write a program that can be used by a ski resort to keep track if local snow conditions for one week.
Llana [10]

Answer:

The java program is as follows.  

import java.lang.*;  

import java.util.Scanner;  

public class Main  

{  

//array declaration  

static int weekdays=7;  

static int[] snowfall_inch = new int[weekdays];  

static String[] snowfall_date = new String[weekdays];  

//variables to store average and maximum  

static double avg;  

static int max;  

public static void main(String[] args) {  

Scanner sc = new Scanner(System.in);  

System.out.print("Enter the month: ");  

String month = sc.next();  

for(int n=0; n<weekdays; n++)  

{  

System.out.print("\nEnter the date for day "+(n+1)+ ": ");  

snowfall_date[n] = sc.next();  

System.out.print("Enter the inches of snowfall for day "+(n+1) +": ");  

snowfall_inch[n] = sc.nextInt();  

avg = avg + snowfall_inch[n];  

}  

avg = avg/weekdays;  

System.out.printf("The average snowfall for the week is %.4f",avg);  

for(int n=0; n<weekdays-1; n++)  

{  

if(snowfall_inch[n] < snowfall_inch[n+1])  

max=snowfall_inch[n+1];  

}  

System.out.println("\nThe maximum snowfall for the week is "+max);  

}  

}  

OUTPUT  

Enter the date for day 2: 12-2-2019

Enter the inches of snowfall for day 2: 23  

Enter the date for day 3: 12-3-2019

Enter the inches of snowfall for day 3: 13  

Enter the date for day 4: 12-4-2019

Enter the inches of snowfall for day 4: 14  

Enter the date for day 5: 12-5-2019

Enter the inches of snowfall for day 5: 34  

Enter the date for day 6: 12-6-2019

Enter the inches of snowfall for day 6: 34  

Enter the date for day 7: 12-7-2019

Enter the inches of snowfall for day 7: 22

The average snowfall for the week is 21.7143  

The maximum snowfall for the week is 34  

Explanation:

1. Two arrays are declared to store dates and snowfall inches with string and integer datatypes respectively.  

2. Variables are declared to store maximum and average snowfall values with integer and double datatypes respectively.  

3. User input is taken for the month, and the dates and snowfall inch values for a week. The input is taken in for loop.  

4. Next, for loop is used to find the average and maximum snowfall of the week.  

5. These values are displayed to the user as shown in the output.

5 0
4 years ago
Additional chemical hazards training must be provided to employees:
poizon [28]
B when new hazards are introduced into the workplace
7 0
3 years ago
Your location has been assigned the 172.149.254.0 /24 network. You are tasked with dividing the network into 13 subnets with the
ira [324]
  • The subnet mask would be a 32-bit integer which is formed by assigning the host bits to all 0's and the networking bits to so many 1's.
  • In this method, the subnetting separates the IP address between host and network addresses.
  • The subnet mask covers an IP address with its 32-bit number, thus the term "mask".

Given:

Network IP address \bold{= 172.149.254.0 /24}

Subnet numbers \bold{= 13}

Calculating the borrow bits:

\to  \bold{= ceil(\log_{2} 13) = 4 \ bits}

a)

Calculating the dotted decimal value for the subnet mask:

\to \bold{11111111.11111111.11111111.00000000}\\\\\to \bold{255.255.255.240}\\\\

b)

The additional bits which will be needed to mask the subnet mask that is = 4.

Learn more: brainly.com/question/2254014

4 0
3 years ago
Levi wants to run 5 commands sequentially, but does not want to create a shell script. He knows that each command is going to ta
disa [49]

Levi can use the bash command to type all the commands on the same line to type one after the other character without requiring input.

<u>Explanation</u>:

  • He wants to run five commands. For one command it will take exactly 20 minutes. So it will take one hour forty minutes.
  • To type all of the commands on the same line Levi should use the bash command. For inserting the bash command Levi should use backslash \ as the last character of the line.
6 0
3 years ago
Write a SELECT statement that returns one row for each customer that has orders with these columns:
d1i1m1o1n [39]

Answer:

SELECT email_address,

SUM(item_price * Quantity) AS item_price_total,

SUM(discount_amount * Quantity) AS discount_amount_total

FROM Customers c

JOIN Orders o ON c.CustomerID = o.CustomerID

JOIN Order_Items oi ON o.OrderID = oi.OrderID

GROUP BY email_address

ORDER BY item_price_total DESC

Explanation:

In this SQL statement the SELECT statement selects the following columns:

email_address

item_price

Quantity

discount_amount

There are two tables Customers and Order_Items

SUM aggregate function is used to add the values of the product of the columns discount_amount and Quantity. It is also used to get the sum of the product of two columns discount_amount and Quantity.

A new temporary column named item_price_total is used to name the sum of the product of two columns discount_amount and Quantity using AS which is ALIAS and it is used to give a name to some columns or a table.

Similarly discount_amount_total name is given to the column which calculate the sum of the product of two columns i.e. discount_amount and Quantity.

JOIN is used here to join the columns from the tables Order_items and Customers.

GROUP BY is used to group the result of rows and is used with functions like SUM. Here the rows are grouped by the email address.

ORDER BY is used to order the result. Here the result is ordered by item_price_total in descending  order.

This SELECT statement can also be written as following:

SELECT c.email_address,

SUM(o.item_price * o.Quantity),

SUM(o.discount_amount * o.quantity)

FROM customer c

JOIN Order_Items o ON o.id = c.id

GROUP BY c.email_address

7 0
4 years ago
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