If five quarts of paint are needed for 250 square-feet of room, 19 quarts of paint will cover how many square feet of room?

What are the sine, cosine, and tangent of circle = 3pi/4 radians?

KengaRu [80]

if you don't have a Unit Circle yet, this is a good time to get one, you can find many online, check maybe in yahoo images, or google images.

Check the picture below.

notice the section encircled in purple.

7 0

3 years ago

Somebody help me.....

Elan Coil [88]

Answer:

in my knowledge

26 , 31 , 36 , 41 , 46

rule:5

cause 26+5=31

31+5=36

36+5=41

41+5=46 and so on...

8 0

3 years ago

Variable m is 9 more than variable p. Variable m is also 8 less than variable p. Which pair of equations best models the relatio

mrs_skeptik [129]

Answer:

the answer would be 1 but there are no equations

Step-by-step explanation:

4 0

3 years ago

PLEASE HELP ME <br>...This is my homework and I don't understand how to do it.

musickatia [10]

The probability that a point chosen at random lies in the shaded region is 0.28

<h3>Calculating the area of a shaded region and probability</h3>

From the question, we are to find the probability that a point chosen at random lies in the shaded region.

The shaded region is a triangle.

The probability that a point chosen at random lies in the shaded region = Area of the triangle / Area of the circle

First, we will calculate the unknown side of the triangle

Let the unknown side be x.

Then, from the <em>Pythagorean theorem</em>, we can write that

12² = 6² + x²

144 = 36 + x²

x² = 144 - 36

x² = 108

x = √108

x = 6√3

From formula,

Area of a triangle = 1/2 × base × height

Area of the triangle = 1/2 × 6 × 6√3

Area of the triangle = 18√3 square units

Now, we will determine the area of the circle

Area of a circle = πr²

Where r is the radius

From the given information,

Diameter of the circle = 12

But,

Radius = Diameter / 2

Therefore,

r = 12/2

r = 6

Thus,

Area of the circle = 3.14 × 6²

Area of the circle = 113.04 square units

Now,

The probability that a point chosen at random lies in the shaded region = 18√3 / 113.04

The probability that a point chosen at random lies in the shaded region = 0.2758

The probability that a point chosen at random lies in the shaded region ≈ 0.28

Hence, the probability is 0.28

Learn more on Calculating area of a shaded region here: brainly.com/question/23629261

#SPJ1

4 0

1 year ago

ank A contains 80 gallons of water in which 20 pounds of salt has been dissolved. Tank B contains30 gallons of water in which 5

adell [148]

Answer:

$\frac{dx}{dt}=2-\frac{3}{40}x+\frac{y}{15}$

$\frac{dy}{dt}=\frac{3}{40}x-\frac{y}{5}$

x(0)=20,y(0)=5

Step-by-step explanation:

We are given that

Tank A contains water=80 gallons

x(0)=20,y(0)=5

Tank B contains water=30 gallons

Rate=4 gallon/min

Concentration of salt is pumped into tank=0.5 pound /gallon of water

Solution pumped from tank A to tank B at the rate=6 gallons/min

Solution pumped from tank B to tank A at the rate=2gallon/min

Solution from tank B is pumped out of the system at the rate=4 gallon/min

We have to find the DE at time t

For x

Rate in= $0.5\times 4+y(t)/30\times 2$

Rate in= $2+y/15$

Rate out= $x/80\times 6$

Rate out=3x/40[/tex]

$\frac{dx}{dt}=$ Rate in-Rate out

$\frac{dx}{dt}=2+y/15-3x/40$

$\frac{dx}{dt}=2-\frac{3}{40}x+\frac{y}{15}$

For y

Rate in= $x/80\times 6$

Rate in=3/40x

Rate out= $y/30\times (4+2)$

Rate out=y/5

$\frac{dy}{dt}=$ Rate in-Rate out

$\frac{dy}{dt}=\frac{3}{40}x-\frac{y}{5}$

8 0

2 years ago