4 years ago

Any one can help me with problem 4?

Mathematics

1 answer:

Travka [436]4 years ago

3 0

One is 55%

Two is 190%

Three is 57

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Solve for [0,2pi): 3sin^2x-6sinx=0

Ainat [17]

Given the equation :

$3\sin ^2x-6\sin x=0$

Let: y = sin x

So,

$\sin ^2x=y^2$

the given equation will be:

$3y^2-6y=0$

Solve for y, take 3y as a common:

$\begin{gathered} 3y(y-2)=0 \\ 3y=0\rightarrow y=0 \\ y-2=0\rightarrow y=2 \end{gathered}$

so,

$\begin{gathered} y=0\rightarrow\sin x=0\rightarrow x=0or\pi \\ y=2\rightarrow\sin x=2 \end{gathered}$

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So, sin x = 2 ( is rejected)

So, the answer will be: x ={ 0 , pi }

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1 year ago

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jenyasd209 [6]

Answer:

hmmmm........

Step-by-step explanation:

radius is 4/2=2m

volume of the cylinder is equal

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3 years ago

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Step-by-step explanation:

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geniusboy [140]

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