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3 years ago

8

Does anyone know this?

1 answer:

Tresset [83]3 years ago

3 0

<ABC would equal 106

seeing in triangle ABD angle A equals 67 you would multiply that by 2 and then subtract it from 180 to get 46, and then triangle DBC all the angles would equal 60. so then add 46 to 60 to get 106 the measure of <ABC

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The population of Mathlandia in 1995 was 23,473 and was projected to grow at a rate of 12% per decade. Predict the population in

lbvjy [14]

Answer:

$27,822$

Step-by-step explanation:

Let

t-----> the time in decade

P----. the population

we know that

$P=23.473(1+0.12)^{t}$

we have

$t=(2010-1995)/10=15/10=1.5\ decade$

substitute

$P=23.473(1.12)^{1.5}=27,822$

8 0

3 years ago

Karl used his credit card to buy a 90-inch HD flat-screen TV for $2,600. The credit card company charges 28% compound interest p

uysha [10]

Answer:

6000 is the answer lol I know it is cause I am in math

5 0

3 years ago

A runner runs 8 miles in 92 minutes. What is the runners unit rate?

KiRa [710]

For this case, what we must do is calculate the speed of the runner.

We have then that the speed is given by:

$v =\frac{d}{t}$

Where,

d: distance

t: time

Substituting values we have:

$v = \frac{8}{92}$

$V = 0.09 \frac{miles}{minutes}$

Answer:

the runners unit rate is:

$V = 0.09 \frac{miles}{minutes}$

5 0

2 years ago

Read 2 more answers

Find an equation of the tangent to the curve x =5+lnt, y=t2+5 at the point (5,6) by both eliminating the parameter and without e

svet-max [94.6K]

ANSWER

$y = 2x -4$

EXPLANATION

Part a)

Eliminating the parameter:

The parametric equation is

$x = 5 + ln(t)$

$y = {t}^{2} + 5$

From the first equation we make t the subject to get;

$x - 5 = ln(t)$

$t = {e}^{x - 5}$

We put it into the second equation.

$y = { ({e}^{x - 5}) }^{2} + 5$

$y = { ({e}^{2(x - 5)}) } + 5$

We differentiate to get;

$\frac{dy}{dx} = 2 {e}^{2(x - 5)}$

At x=5,

$\frac{dy}{dx} = 2 {e}^{2(5 - 5)}$

$\frac{dy}{dx} = 2 {e}^{0} = 2$

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

$y-y_1=m(x-x_1)$

$y - 6 = 2(x - 5)$

$y = 2x - 10 + 6$

$y = 2x -4$

Without eliminating the parameter,

$\frac{dy}{dx} = \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }$

$\frac{dy}{dx} = \frac{ 2t}{ \frac{1}{t} }$

$\frac{dy}{dx} = 2 {t}^{2}$

At x=5,

$5 = 5 + ln(t)$

$ln(t) = 0$

$t = {e}^{0} = 1$

This implies that,

$\frac{dy}{dx} = 2 {(1)}^{2} = 2$

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

$y-y_1=m(x-x_1)$

$y - 6 = 2(x - 5) =$

$y = 2x -4$

5 0

3 years ago

Matteo is following this recipe to make a cake.

stepan [7]

Answer:

6×3+5×3+7×3+3×3+2×3=69

5 0

2 years ago