N equals 1.125. Percent are y’all going to be doing okay now lol ima is my life day to wiwiwiwiwiwiwow
Answer:
The steps will be :
1. Draw both equations into the graph.
2. Look for the coordinates where they intersect(curve and line crosses each other). So the coordinates will be (-2,0) and (3,5).
3. The x-value of the coordinates will the solution to the equations.
4. Therefore, the answer will be -2 and 3.
Hello from MrBillDoesMath!
Answer:
See Discussion below
Discussion:
(sinq + cosq)^2 = => (a +b)^2 = a^2 + 2ab + b^2
(sinq)^2 + (cosq)^2 + 2 sinq* cosq => as (sinx)^2 + (cosx)^2 = 1
1 + 2 sinq*cosq (*)
Setting a = b = q in the trig identity:
sin(a+b) = sina*cosb + cosa*sinb
sin(2q) = (**)
sinq*cosq + cosq*sinq => as both terms are identical
2 sinq*cosq
Combining (*) and (**)
(sinq + cosq)^2 = 1 + 2sinq*cosq => (**) 2sinq*cosq = sqin(2q)
= 1 + sin(2q)
Hence
(sinq + cosq)^2 = 1 + sin(2q) => subtracting 1 from both sides
(sinq + cosq)^2 - 1 = sin(2q)
The last statement is what we are trying to prove.
Thank you,
MrB
Answer:
K'= (-2, 4)
Step-by-step explanation:
First we are going to rotate our point 270° counterclockwise.
The rule for a 270° counterclockwise rotation is 
, which means that we just need to interchange the coordinates of the point and change the sign of the x-coordinate:
Now, to shift the point 3 units down, we just need to subtract 3 units from the new y-coordinate of our resulting point form the previous procedure:
We can conclude that the coordinates of K' are (-2, 4)
Step-by-step explanation:
x²=a²+b²
x=√6²+12²
x=√180
x=3√2v
y²=16²+12²
y=√400
y=20
