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garri49 [273]
4 years ago
9

16) When diagonal WY is drawn in trapezoid WXYZ, why will Angle XYW and angle ZWY always be congruent?

Mathematics
1 answer:
IrinaVladis [17]4 years ago
6 0
The answer to this question would be D
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Mrs. Lowe gave a countries project to three of her students George, Martin, and Andrew. Use an organized list to show all the po
4vir4ik [10]

Answer:

  1. George
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Step-by-step explanation:

5 0
4 years ago
Identify the angles of rotational symmetry for the figure.
babunello [35]

Answer:

45 120 144 that the ones to pick

8 0
3 years ago
Rewrite each equation in standard form. <br><br> 4 and 5 only
nekit [7.7K]

Answer:

4) 2=4x-3y

5) 51=21x-3y

Step-by-step explanation:

I gave it my best shot, I used fraction busters to cancel out the fractions and then I used simple math and distributive property. Hope it helps.

7 0
3 years ago
D-10-2d+7=8-10-3d can someone solve this
tekilochka [14]
D - 10 - 2d + 7 = 8 - 10 - 3d
- d - 3 = - 2 - 3d
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Hope this helps.
7 0
4 years ago
Let V be the volume of the solid obtained by rotating about the y-axis the region bounded y = sqrt(25x) and y = x^2/25. Find V b
Westkost [7]

Explanation:

Let f(x) = \sqrt{25x} and g(x) = \frac{x^2}{25}. The differential volume dV of the cylindrical shells is given by

dV = 2\pi x[f(x) - g(x)]dx

Integrating this expression, we get

\displaystyle V = 2\pi\int{x[f(x) - g(x)]}dx

To determine the limits of integration, we equate the two functions to find their solutions and thus the limits:

\sqrt{25x} = \dfrac{x^2}{25}

We can clearly see that x = 0 is one of the solutions. For the other solution/limit, let's solve for x by first taking the square of the equation above:

25x = \dfrac{x^4}{(25)^2} \Rightarrow \dfrac{x^3}{(25)^3} = 1

or

x^3 =(25)^3 \Rightarrow x = \pm25

Since we are rotating the functions around the y-axis, we are going to use the x = 25 solution as one of the limits. So the expression for the volume of revolution around the y-axis is

\displaystyle V = 2\pi\int_0^{25}{x\left(\sqrt{25x} - \frac{x^2}{25}\right)}dx

\displaystyle\:\:\:\:=10\pi\int_0^{25}{x^{3/2}}dx - \frac{2\pi}{25}\int_0^{25}{x^3}dx

\:\:\:\:=\left(4\pi x^{5/2} - \dfrac{\pi}{50}x^4\right)_0^{25}

\:\:\:\:=4\pi(3125) - \pi(7812.5) = 14726.2

4 0
3 years ago
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