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garri49 [273]
4 years ago
9

16) When diagonal WY is drawn in trapezoid WXYZ, why will Angle XYW and angle ZWY always be congruent?

Mathematics
1 answer:
IrinaVladis [17]4 years ago
6 0
The answer to this question would be D
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12x² - x - 20 = (4x+5)(3x−4)

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Reactant A can participate in both of these reactions:
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The activation energy is the amount of energy required to initiate a certain reaction. The activation energy may considered as an "energy barrier" that has to be overcome in order for a reaction to begin. If a reaction has a lower activation energy, then it will occur more easily and at a faster rate than a reaction with a higher activation energy. Therefore, the reason that reaction 1 is faster than reaction 2 is because it has a lower activation energy than reaction 2.
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What is 0.617 in fraction form
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617/1000

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Pythagorean triples are given by the formulas x2 - y2, 2xy, and x2 + y2. Use the formulas for the Pythagorean triples to prove w
Arte-miy333 [17]
Let k be an integer. Suppose there is a triangle with legs of length 16 and 2k+1. Then by the Pythagorean theorem, the length of the hypotenuse should be

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4 0
3 years ago
Hi. Please help me with these questions <br> See image for question.Answer no 6 and 7
Gnom [1K]

Answer:

  • 6. See solution
  • 7. k = 2, k = -6

Step-by-step explanation:

6.

<u>Given equation:</u>

  • 2(x + 2)² + p(x + 1) = 0
  • The sum of the roots is q1 and the product of the roots is q2

Need to show that q1+q2 = 0

<h3>Solution</h3>

<u>Bringing the equation into standard form of ax² + bx + c = 0:</u>

  • 2(x + 2)² + p(x + 1) = 0
  • 2x² + 8x + 8 + px + p = 0
  • 2x² + (p + 8)x + (p + 8) = 0

<u>Sum of the roots: </u>

  • q1 = - b/a = -(p + 8)/2

<u>Product of the roots:</u>

  • q2 = c/a = (p + 8)/2

<u>We see that q1 and q2 are opposite numbers, therefore their sum equals zero:</u>

  • q1 + q2 = -(p + 8)/2 +  (p + 8)/2 = 0

=============================================

7.

<u>Given quadratic equation:</u>

  • x² - (k + 2)x + 4 = 0
  • It has equal roots

Need to find the possible values of k

<h3>Solution</h3>

<u>When the quadratic equation has equal roots, then its discriminant is equal to zero:</u>

  • D = 0
  • √b² - 4ac = 0
  • √(-k -2)² - 4*1*4 = 0
  • √k² + 4k + 4 - 16 = 0
  • √k² + 4k - 12 = 0
  • k² + 4k - 12 = 0
  • k = {-4 ± √4² -4*1*(-12)}/2
  • k = (-4 ± √16 + 48)/2
  • k = (-4±√64)/2
  • k = -2 ± 4
  • k = 2, k = -6
7 0
3 years ago
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