Answer:
The correct answer is -
A) BbTt x bbTt
B) .5^4 or 1/16 or 0.0625
Explanation:
As it is given that Brachydactylus and PTC tasters both traits are autosomal dominant conditions which mean only one allele would be enough.
For Branchydactylus and For tasting : man and women will be heterogeneous.
Hence,
The Genotype of man = BbTt
The Genotype of wife = bbTt
b. Answer = 0.0625
For Branchydactylus:
Bb X bb
Possible genotypes:
B b
b Bb( Brachydactylus) bb(normal)
b Bb (Brachydactylus) bb (normal)
The probability of a single child being Branchydactylus = 2/4 = 0.5
So, Probability of all 4 child being Branchydactylus = .5 x .5 x .5 x .5 = 0.0625
Answer:
c. it can be considered a global ecosystem
<span>One that is made of nitrogen and hydrogen is definitely inorganic. Inorganic has these molecules in them.</span>
Answer:
Mutations in introns create alternative splicing site which in turn make mRNA with reduced or no translation.
Explanation:
Introns regulate the splicing of heterogenous RNA during post transcriptional modifications as well as affect the stability of mature mRNA. The stable mRNA is more likely to be translated into proteins. So, introns also regulate the translation of mRNA.
In human beta thalassemia, mutations in intron create alternative splicing sites which in turn affect the formation of beta globin chain of hemoglobin. Lack of beta globin chain reduces the amount of functional hemoglobin and causes anemia.
