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Elenna [48]
3 years ago
7

At track practice,Sheila worked on the long jump. Her first jump measured 3 yards, 2 feet, 8 inches. Her second jump measured 2

yards,1 foot, 10 inches. What was the total lenght of shielas two jumps? Express your answer in feet
Mathematics
1 answer:
jolli1 [7]3 years ago
7 0
The length is 19.5 feet. this is because when you add the yards, it equals 15 feet. Next, add 1 + 2 feet from the first and second jump. 10+8 inches equal 1.5 feet. Next, add 15 feet+3 feet+1.5 feet to get 19.5 feet.
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Zigmanuir [339]

Answer:

The integrals was calculated.

Step-by-step explanation:

We calculate integrals, and we get:

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2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}

3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}

4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}

5)  \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=

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6)  ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x

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6 0
3 years ago
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Answer:

(120 * 32) + 160,500

Step-by-step explanation:

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3 years ago
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bearhunter [10]

Answer:

For b = 7, the expression equals 15.

Step-by-step explanation:

6b + 8 - 5b

Substitute the variable b = 7.

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42 + 8 - 35

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3 years ago
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Answer:

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