How to do this problem

Choose the correct solution and graph for the inequality.

Y_Kistochka [10]

The answer to question one would be "D" y<-3

For question two the answer would be "C" x<5

Hope that helps!

6 0

3 years ago

On a hot summer day, Jen is in a foreign country. She wonders which

tino4ka555 [31]

Answer: Celsius scale

Step-by-step explanation:

Fahrenheit scale is established from the freezing and boiling temperatures of water, which are:

Freezing temperature of water: $32\°F$

Boiling temperature of water: $212\°F$

Which means that all temperatures below $32\°F$ are below the freezing temperature of water. Therefore, if Jen is in the Summer season, which is characterized by high temperatures, it is incoherent to think that the thermometer is using the Farenheit scale.

Now, $30\°C$ is in accordance with the high temperatures recorded in the summer season.

If we want to know how much $30\°C$ is in Farenheits, we must use the following conversion formula:

$(30\°C)(\frac{9}{5})+32=86\°F$

8 0

3 years ago

Sam is making trail mix the recipe requires 1 1/2 cups of raisins for 6 cups of peanuts. How many cups will he of raisins will h

LuckyWell [14K]

You will need .5 cups of rasi w

7 0

3 years ago

According to the article "Characterizing the Severity and Risk of Drought in the Poudre River, Colorado" (J. of Water Res. Plann

mihalych1998 [28]

Answer:

(a) P (Y = 3) = 0.0844, P (Y ≤ 3) = 0.8780

(b) The probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

Step-by-step explanation:

The random variable Y is defined as the number of consecutive time intervals in which the water supply remains below a critical value y₀.

The random variable Y follows a Geometric distribution with parameter p = 0.409.

The probability mass function of a Geometric distribution is:

$P(Y=y)=(1-p)^{y}p;\ y=0,12...$

(a)

Compute the probability that a drought lasts exactly 3 intervals as follows:

$P(Y=3)=(1-0.409)^{3}\times 0.409=0.0844279\approx0.0844$

Thus, the probability that a drought lasts exactly 3 intervals is 0.0844.

Compute the probability that a drought lasts at most 3 intervals as follows:

P (Y ≤ 3) = P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3)

$=(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409+(1-0.409)^{2}\times 0.409\\+(1-0.409)^{3}\times 0.409\\=0.409+0.2417+0.1429+0.0844\\=0.8780$

Thus, the probability that a drought lasts at most 3 intervals is 0.8780.

(b)

Compute the mean of the random variable Y as follows:

$\mu=\frac{1-p}{p}=\frac{1-0.409}{0.409}=1.445$

Compute the standard deviation of the random variable Y as follows:

$\sigma=\sqrt{\frac{1-p}{p^{2}}}=\sqrt{\frac{1-0.409}{(0.409)^{2}}}=1.88$

The probability that the length of a drought exceeds its mean value by at least one standard deviation is:

P (Y ≥ μ + σ) = P (Y ≥ 1.445 + 1.88)

= P (Y ≥ 3.325)

= P (Y ≥ 3)

= 1 - P (Y < 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2)

$=1-[(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409\\+(1-0.409)^{2}\times 0.409]\\=1-[0.409+0.2417+0.1429]\\=0.2064$

Thus, the probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

6 0

3 years ago

Find the value of x for this figure

Lera25 [3.4K]

Answer:

x = 101°

Step-by-step explanation:

15 + 25 + 39 + x = 180

79 + x = 180

x = 101

8 0

3 years ago

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