Answer:
Step-by-step explanation:
50.
line AB that has the points (2,5) and (9,2) hhas the slope
m= (y2-y1) / (x2-x1)= 5-2 / 2-9 = 3/-7 = -3/7
Parallel line have the same slope so m= -3/7 for the line that has the point (-3,4).
Point-slope equation is y-y1 = m (x-x1), y -4 = -3/4 (x+3) or
you can writte it as y= (-3/4)x - 9/4 +16/4 so y = (-3/4)x + 7/4
51.
line PQ has slope m= -6+1 / 4-6 = -5/-2 = 5/2
Perpendicular lines have their slope negative reciprocal of eachother so the line that goes trough the point (1,3) has the slope m= -2/5
y-3 = -2/5 (x-1)
Find the midpoint:
m= x1+x2/2; y1+y2/2
m= 9+-1/2; 8+-2/2
m= 8/2; 6/2
m= (4,3)
(4,3) is your answer.
I hope this helps!
~kaikers
On the top problem: Angle A and Angle B are a right angle so it equals 90 degrees. If Angle B is 50 degrees that makes Angle A 40 degrees. Angle A and Angle C is a straight line and equals 180 degrees so if Angle A equals 40 degrees that means Angle C equals 140 degrees.
Answer:
1/4
Step-by-step explanation:
3 out of 12 stored over 10:
3 / 12
simplify
1/4
