Answer:
The minimum sample needed to provide a margin of error of 3 or less is 52.
Step-by-step explanation:
The confidence interval for population mean (<em>μ</em>) is:
The margin of error is:
<u>Given:</u>
MOE = 3
<em>σ </em>= 11
The critical value for 95% confidence interval is: 
**Use the <em>z</em>-table for critical values.
Compute the sample size (<em>n</em>) as follows:
Thus, the minimum sample needed to provide a margin of error of 3 or less is 52.
Figure out 5% of 30,000: .05 x 30,000 = 1,500
Multiply 1,500 by the number years, but subtract the first year (as you don't receive a bonus) : 1,500 x 39 = 58,500
Now add the bonus with the initial salary: 58,500 + 30,000 = 88,500.
THE ANSWER IS $88,500!!! :)
<span>The multiples of 6. Answer : 6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96,102,108,114,120,126,132,138,144,150,156,1</span>
The number of matinee movies attended is 4.
The number of a evening show movies attended is 2.
<u>Step-by-step explanation:</u>
- Let x represent the number of matinee movies attended.
- Let y represent the number of evening show movies attended.
- Alejandro went to see a total of 6 movies.
Therefore, from the given data the equation can be framed as :
⇒ x + y = 6 ----------(1)
- The cost of a matinee is $7.
- The cost of an evening show is $12.
- Alejandro spent a total of $52.
Therefore, from the given data the equation can be framed as :
⇒ 7x + `12y = 52 ---------(2)
<u>To solve the equations for x and y values :</u>
Mulitply eq (1) and by 7 and subtract eq (2) from eq (1),
7x + 7y = 42
- <u>(7x + 12y = 52)</u>
<u> - 5y = - 10 </u>
⇒ y = 10/5
⇒ y = 2
The number of a evening show movies attended is 2.
Substitute y=2 in eq (1),
⇒ x+2 = 6
⇒ x = 6-2
⇒ x = 4
The number of matinee movies attended is 4.
