Can you prove this congruent? Using what theorem/postulate?
1 answer:
I'd say that, if the angles S and U are equal, as the SV and UV segments move towards each other, they meet at vertex V, the angles they make, angle SVT and UVT, have to be equal, because the side TV is shared by both, and has the same direction.
now, side TV is on both triangles, and is shared by both, so is the same length, so TV on one triangle is equal to TV on the other
check the picture below
so, you have one Angle, another Angle, and then a Side
A A S
now, side TV is on both triangles, and is shared by both, so is the same length, so TV on one triangle is equal to TV on the other
check the picture below
so, you have one Angle, another Angle, and then a Side
A A S
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Answer:
Step-by-step explanation:
It's given in the question that;
The spinner is divided into 11 equal sections from 0 to 10.
You spin the spinner <u>ONCE!</u><u> </u>
The total number of possibilities is six, and the total number of sample spaces is 11.
So the probability of getting an even number is;
I hope this helps!