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Snowcat [4.5K]
3 years ago
7

Brine is a solution of salt and water. If a tub contains 50 pounds of 5% solution of brine, how much water (to the nearest tenth

lb.) must evaporate to change it to an 8% solution?

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
5 0
The only important thing here is the ratio between the salt and the entire solution. The salt makes up 5% of the entire solution, which is 50lbs. 5% of 50lbs is 2.5lbs. So, we want to know how much brine must be left to create a 8% solution with 2.5lbs of salt. To do this, make the amount of brine solution a variable, x. So, you know that 2.5 should be 8% of x. This can be modeled by the equation 2.5/x = 0.08. Solve for x. Now that you've got the amount of brine, 31.25lbs, you've got to subtract that from the original to see how much water has evaporated. 50 - 31.25 = 18.75. Round up to 18.8lbs and there's your answer!

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HELP! WILL AWARD BRAINLIEST TO WHOEVER ANSWERS BOTH PARTS CORRECTLY!!
rewona [7]

check the picture below.

now, we're assuming the trapezoid is an isosceles trapezoid, namely AD = BC, and therefore the triangles are twins.

incidentally, b is the height of the trapezoid and likewise is also the altitude or height of the concrete triangle.

so we can simply get the area o the trapezoid, notice the bottom base is a+185+a, and then get the area of the concrete triangle and subtract the triangle from the trapezoid, what's leftover is just the vegetation area.

\bf \begin{cases} a=283\cdot cos(80^o)\\ a\approx 49.14\\ --------\\ b=283\cdot sin(80^o)\\ b\approx 278.70 \end{cases}\\\\ -------------------------------\\\\ \textit{area of a trapezoid}\\\\ A=\cfrac{h(x+y)}{2}~~ \begin{cases} x,y=\stackrel{bases}{parallel~sides}\\ h=height\\ ----------\\ x=185\\ y\approx \stackrel{a+185+a}{283.28}\\ h\approx\stackrel{b}{278.70} \end{cases} \\\\\\ A=\cfrac{278.70(185+283.28)}{2}\implies A\approx 65254.818

so that's the area of the trapezoid, now let's get the area of the triangle.

\bf \stackrel{triangle}{\cfrac{1}{2}(185)(b)}\implies \cfrac{1}{2}(185)(278.70)\qquad \approx 25779.80\\\\ -------------------------------\\\\ \stackrel{\textit{area for vegetation}}{\stackrel{\textit{area of trapezoid}}{65254.818}~~-~~\stackrel{\textit{area of triangle}}{25779.80}}\implies 39475.018

since we know 36 yd² cost 12 bucks, then how much will it be for 39475.018 yd²?

\bf \begin{array}{ccll} yd^2&\$\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 36&12\\ 39475.018&x \end{array}\implies \cfrac{36}{39475.018}=\cfrac{12}{x}\implies x=\cfrac{39475.018\cdot 12}{36} \\\\\\ x\approx 13158.339\overline{3}

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mr Goodwill [35]

Answer: A

Step-by-step explanation:

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