A car is traveling at when the driver sees an accident m ahead and slams on the brakes. What constant deceleration is required t
1 answer:
Answer:
Deceleration = units/sec^2
Step-by-step explanation:
Given that a car is traveling at when the driver sees an accident m ahead and slams on the brakes.
i.e. if he is coming with speed v units/sec say, he has to make his velocity 0.
Distance travelled = m units
Initial velocity = v
Final velocity =0
Use the third formula as
So he has to apply an acceleration of units/sec^2 to stop the car in time to avoid a pile up.
Deceleration = units/sec^2
You might be interested in
Answer:
There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.
Step-by-step explanation:
For each passenger, there are only two outcomes possible. Either they show up for the flight, or they do not show up. This means that we can solve this problem using binomial distribution probability concepts.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinatios of x objects from a set of n elements, given by the following formula.
And is the probability of X happening.
A probability is said to be unusually low if it is lower than 5%.
For this problem, we have that:
There are 200 reservations, so .
A passenger consists in a passenger not showing up. There is a .0995 probability that a passenger with a reservation will not show up for the flight. So .
Find the probability that when 200 reservations are accepted for United Flight 15, there are more passengers showing up than there are seats available.
X is the number of passengers that do not show up. It needs to be at least 18 for the flight not being overbooked. So we want to find , with
. We can use a binomial probability calculator, and we find that:
.
There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.
Answer:
Step-by-step explanation:
The plot chart below best represents the relationship between stress and productivity in the workplace. As seen in the chart both high and low levels of stress equate to very low productivity levels for employees in the workplace. While just enough stress creates very productive employees. This tends to be because employees are worried about the possibility of losing their jobs so they work hard in order to keep the job but are not so worried that they think it will happen tomorrow and become burned out.
