Plzzzz help!! Me find x

Mathematics

1 answer:

vivado [14]3 years ago

3 0

Answer:

x=-4

Step-by-step explanation:

These two angles have to equal 180 because they are opposite of each other. Therefore, the equation will be 129+x+x+59=180. You add all common terms. 2x+188=180. You want to isolate x so you have to subtract both sides by 188. Therefore, the equation will be 2x=-8. Divide both sides by 2 to isolate x. x=-8/2. This is equal to x=-4.

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Lupita rides a taxi that charges a flat rate of $6.75 plus $3.20 per mile. If the taxi charges Lupita $40.03 in total for her tr

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Hello! In order to understand this question, we need to take a look at the content that is involved.

Lupita pays $40.03 in total. Meaning that's where we are going to start if we want to find out how many miles her ride was. Since the taxi charges a flat rate of $6.75. We would want to subtract it from her total value because we only work with that flat rate once. Which ends up giving us $33.28. From there, we don't need to worry about the flat rate anymore and we now focus on the mileage. If it costs $3.20 per mile, then we can simply divide the amount after to flat rate by the cost per mile, to figure out how many miles she has gone. In the end, you will get 10.4 miles.

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3 years ago

What is the peremeter of this polygon? (With picture)

lyudmila [28]

Check the picture below.

so.. simply, use the distance formula, to get their length an add them up, and that's the perimeter of the polygon.

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -1}}\quad ,&{{ 2}})\quad 
% (c,d)
&({{ 2}}\quad ,&{{ 4}})\\
&({{ 2}}\quad ,&{{ 4}})\quad 
% (c,d)
&({{ 3}}\quad ,&{{ -2}})\\
&({{ 3}}\quad ,&{{ -2}})\quad 
% (c,d)
&({{ -2}}\quad ,&{{ -3}})\\
&({{ -2}}\quad ,&{{ -3}})\quad 
% (c,d)
&({{ -1}}\quad ,&{{ 2}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf -------------------------------\\\\
d=\sqrt{[2-(-1)]^2+(4-2)^2}\implies d=\sqrt{(2+1)^2+(2)^2}
\\\\\\
d=\sqrt{3^2+2^2}\implies \boxed{d=\sqrt{13}}\\\\
-------------------------------\\\\
d=\sqrt{(3-2)^2+(-2-4)^2}\implies d=\sqrt{1^2+(-6)^2}\implies \boxed{d=\sqrt{37}}\\\\
-------------------------------\\\\
d=\sqrt{(-2-3)^2+[-3-(-2)]^2}\implies d=\sqrt{(-5)^2+(-3+2)^2}
\\\\\\
d=\sqrt{(-5)^2+(-1)^2}\implies \boxed{d=\sqrt{26}}$

$\\\\
-------------------------------\\\\
d=\sqrt{[-1-(-2)]^2+[2-(-3)]^2}\implies d=\sqrt{(-1+2)^2+(2+3)^2}
\\\\\\
d=\sqrt{(1)^2+(5)^2}\implies \boxed{d=\sqrt{26}}$

so, those are their lengths, sum them all up, that's the polygon's perimeter.