The resultant velocity is 360.81 m/s and the velocity of the dolphin swims is 11 m/s
Explanation:
The boat travelling is 13.4 m/s
The captain walks on the deck is 1.3 m/s
The resultant velocity = a² + b² = c²
= 13.4² + 1.3²
= 179.56 + 1.69
c² =
c= 360.81 m/s
To find the velocity, the dolphin swims in 55 m and the acceleration is 5.0 s
velocity = distance / acceleration
=
= 11 m/s
Therefore, the velocity is 11 m/s.
Answer:
the final velocity of the object is 53.04 m/s.
Explanation:
Given;
initial velocity of the projectile, u = 50 m/s
displacement of the object, d = 16 m
let the final velocity of the object = v
Apply the following kinematic equation to determine the final velocity of the projectile.
v² = u² + 2gd
v² = 50² + (2 x 9.8 x 16)
v² = 2813.6
v = √2813.6
v = 53.04 m/s
Therefore, the final velocity of the object is 53.04 m/s.
Answer: Reflection by clouds
Explanation:
Only some shortwave radiation from the sun reaches the Earth's surface because solar radiation is being reflected by thick clouds and thin clouds transmit the solar radiation.
About 31 % of solar radiation is reflected by clouds. The tiny water particle scatters 20-90 % of incoming sunlight giving them a bright white appearance.
Answer:
229,098.96 J
Explanation:
mass of water (m) = 456 g = 0.456 kg
initial temperature (T) = 25 degrees
final temperature (t) = - 10 degrees
specific heat of ice = 2090 J/kg
latent heat of fusion =33.5 x 10^(4) J/kg
specific heat of water = 4186 J/kg
for the water to be converted to ice it must undergo three stages:
- the water must cool from 25 degrees to 0 degrees, and the heat removed would be Q = m x specific heat of water x change in temp
Q = 0.456 x 4186 x (25 - (-10)) = 66808.56 J
- the water must freeze at 0 degrees, and the heat removed would be Q = m x specific heat of fusion x change in temp
Q = 0.456 x 33.5 x 10^(4) = 152760 J
- the water must cool further to -10 degrees from 0 degrees, and the heat removed would be Q = m x specific heat of ice x change in temp
Q = 0.456 x 2090 x (0 - (-10)) = 9530.4 J
The quantity of heat removed from all three stages would be added to get the total heat removed.
Q total = 66,808.56 + 152,760 + 9,530.4 = 229,098.96 J
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