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3 years ago

Q1) A motor has a rating power of 20 W and motor is used for 10 s. Calculate the

Physics

1 answer:

Yuki888 [10]3 years ago

5 0

Energy = Power x Time
Energy = 20W x 10s
Energy = 200 joules

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Suppose electrons in a TV tube are accelerated through a potential difference of 2.00 104 V from the heated cathode (negative el

Ivanshal [37]

Answer:

83816746.4254 m/s

Explanation:

m = Mass of electron = $9.11\times 10^{-31}\ kg$

q = Charge of electron = $1.6\times 10^{-19}\ C$

V = Voltage = $2\times 10^4\ V$

The kinetic energy of the electron is

$K=\dfrac{1}{2}mv^2$

Energy is given by

$E=qV$

Balancing the energy

$qV=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{\dfrac{2qV}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\times 2\times 10^4}{9.11\times 10^{-31}}}\\\Rightarrow v=83816746.4254\ m/s$

The velocity of the electrons is 83816746.4254 m/s

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3 years ago

Gunther needs a 75% concentrated solution. When making his solution at room temperature, he could only make a solution that was

jolli1 [7]

Answer:

Heat the solution, dissolve the solute, and let it cool verifying nothing settled out.

Explanation:

7 0

3 years ago

Read 2 more answers

Two forces act on a 6.00-kg object. One of the forces is 10.0 N. If the object accelerates at 2.00 m/s2

liubo4ka [24]

Given :

Two forces act on a 6.00-kg object. One of the forces is 10.0 N.

Acceleration of object 2 m/s².

To Find :

The greatest possible magnitude of the other force.\

Solution :

Let, other force is f.

So, net force, F = 10 + f.

Now, acceleration is given by :

$a=\dfrac{F}{mass}\\\\a= \dfrac{10+f}{6}\\\\\dfrac{10+f}{6}=2\\\\f = 12 - 10\\\\f = 2 \ N$

Therefore, the greatest possible magnitude of the other force is 2 N.

Hence, this is the required solution.

7 0

3 years ago

How is the q of an rlc parallel resonant circuit calculated?

notka56 [123]

Answer:

It is calculated by dividing Resistance, R, by Inductive reactance, XL.

Explanation:

Q is called the Q factor of a resonance circuit. In a parallel resonance circuit, it is calculated by finding the ratio of the power stored in the circuit to the power distributed in the circuit. It is a way of measuring the quality of a circuit or how effective the circuit is.

Q factor is the inverse in the resonance series circuit.

Q factor of a resonance parallel circuit,

R = Resistance

XL = Inductive reactance

3 0

3 years ago

The potential energy of a pear is 5.0 joules. The pear is 4 m high. What is the mass of the apple?

gregori [183]

Answer:

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Explanation:

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4 years ago