<h3><u>Question</u><u>:</u></h3>
A racing car is travelling at 70 m/s and accelerates at -14 m/s^2. What would the car’s speed be after 3 s?
<h3><u>Statement:</u></h3>
A racing car is travelling at 70 m/s and accelerates at -14 m/s^2.
<h3><u>Solution</u><u>:</u></h3>
- Initial velocity (u) = 70 m/s
- Acceleration (a) = -14 m/s^2
- Time (t) = 3 s
- Let the velocity of the car after 3 s be v m/s
- By using the formula,
v = u + at, we have

- So, the velocity of the car after 3 s is 28 m/s.
<h3><u>Answer:</u></h3>
The car's speed after 3 s is 28 m/s.
Hope it helps
Answer: A force can be applied to another object by a direct push, pull, or drag.
Explanation:
Answer:
The value of the acceleration of gravity of the Unknown Planet = 1.14 
Explanation:
length of the pendulum (L)= 1.15 m
Time period (T)= 6.29 seconds
We know that time period of a simple pendulum is given by
⇒ T = 2
×
put the values in the above formula we get
⇒ T = 2
× 
⇒ 6.29 = 2
× 
By solving the above equation we get
⇒ g = 1.14 
This is the value of the acceleration of gravity of the Unknown Planet.
Answer:
Shown below as 'The advantage is that the router will always choose the faster route to send the packet and each connection is independent.'
Explanation:
The advantage is that the router will always choose the faster route to send the packet and each connection is independent.
Hope this helps!
Kind regards
Farah Syed