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Nataly_w [17]
3 years ago
13

Solve this equation. 2(3x+5)=4(2x-3)

Mathematics
2 answers:
Olin [163]3 years ago
4 0
6x+10=8x-12
6x-8x=-12-10
-2x=-22
x=11

Hope this can help.
Viktor [21]3 years ago
3 0

Answer:

<h2>x = 11</h2>

Step-by-step explanation:

2(3x+5) = 4(2x - 3)

<u>First expand the terms</u>

That's

6x + 10 = 8x - 12

6x - 8x + 10 = - 12

- 2x + 10 = - 12

<u>Subtract 10 from both sides</u>

That's

- 2x + 10 - 10 = - 12 - 10

- 2x = - 22

Divide both sides by - 2

We have the final answer as

<h3>x = 11</h3>

Hope this helps you

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Use the order of operations to find the value of the expression 5*2+6-5
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Salutations!

BODMAS also called Order of Operations means:

B- Brackets

O - Order

D- Division

M- Multiplication

A- Addition

S- Subtraction.

5*2+6-5

5*2 =10

10+6=16

16-5=11

Hope I helped (:

have a great day!
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Let f(x) be a continuous function such that f(1) = 3 and f '(x) = sqrt( x^3 + 4 ). What is the value of f(5)?
snow_lady [41]

The value of f(5) is 49.1

Step-by-step explanation:

To find f(x) from f'(x) use the integration

f(x) = ∫ f'(x)

1. Find The integration of f'(x) with the constant term

2. Substitute x by 1 and f(x) by π to find the constant term

3. Write the differential function f(x) and substitute x by 5 to find f(5)

∵ f'(x) =  + 6

- Change the root to fraction power

∵  =

∴ f'(x) =  + 6

∴ f(x) = ∫  + 6

- In integration add the power by 1 and divide the coefficient by the

 new power and insert x with the constant term

∴ f(x) =  + 6x + c

- c is the constant of integration

∵

∴ f(x) =   + 6x + c

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∴ π =   + 6(1) + c

∴ π =  + 6 + c

∴ π = 6.4 + c

- Subtract 6.4 from both sides

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∴ f(x) =   + 6x - 3.2584

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∴ f(5) =   + 6(5) - 3.2584

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3 years ago
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morpeh [17]
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