Question

Writing the quation for a line that goes through the following points (0,3) (1,1

Answer 1

$\huge\boxed{y=-2x+3}$

Start off by finding the slope of the line with the formula $\frac{y_2-y_1}{x_2-x_1}$.

Substitute the values. $\frac{1-3}{1-0}$

Subtract. $\frac{-2}{1}$

Simplify. $-2$

$-2$ is the slope of the line.

Now, use the point-slope formula to create an equation, where $m$ is the slope and $(x_1, y_1)$ is a known point on the line. $y-y_1=m(x-x_1)$

Substitute the values. $y-3=-2(x-0)$

Simplify. $y-3=-2x$

Move the $3$ to create the final equation in slope-intercept form. $\large\boxed{y=-2x+3}$