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Sergio [31]
3 years ago
13

Geometry question any help is appreciated!!

Mathematics
2 answers:
serg [7]3 years ago
6 0
Equation of the circle
(x-h)² + (y-k)² = r²

(h,k) = (-3,6) - coordinates of the center of the circle
r=2 - radius of the circle

(x-(-3))² + (y-6)² = 2²
(x+3)² + (y-6)² = 4
tangare [24]3 years ago
4 0
For this question, the equation I got was (x+3)^2 + (y-6)^2 = r^2.
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Order the angles in each triangle from smallest to largest.
lana [24]

9514 1404 393

Answer:

  B: L, M, N

Step-by-step explanation:

The sides are listed from shortest to longest. The angles opposite these sides will be in order smallest to largest. The name of the opposite angle is the vertex whose name is missing from the side's name.

MN is opposite angle L, the smallest

LN is opposite angle M, the middle-size

LM is opposite angle N, the largest.

Smallest to largest, the angles are ∠L, ∠M, ∠N.

3 0
2 years ago
Please help, thank you
bogdanovich [222]

Answer:

B

Step-by-step explanation:

He asked me to make sure I had enough 20 words. But this question is really simple, Just move c to the right. And then change the symbol.

6 0
2 years ago
Use the discriminant to determine the number and type of solutions the equation has.
White raven [17]
x^2 + 8x + 12 = 0\\ \\a=1 , b= 8, c= 12 \\ \\ \Delta =b^2-4ac = 8^2 -4\cdot1\cdot12= 64-48= 16\\ \\\Delta > 0 \\ \\ Answer : \ C. \ \ two \ rational \ solutions


5 0
2 years ago
Read 2 more answers
I need help with this problem
alexandr402 [8]

Answer:

4*x^4*y^22

Step-by-step explanation:

Your goal here is to REDUCE the given expression to simplest terms.

One way in which to approach this problem would be to rewrite (2x^2y^10)^3 as:  (2x^2*y^8)*y^2*(2x^2*y^10)^2.

Dividing this rewritten expression by 2x^2*y^8 results in:

y^2(2x^2*y^10)^2.

We now need to raise (2x^2*y^10) to the power 2.  Doing this, we get:

4x^4*y^20.

Multiply this by y^2 (see above):

y^2*4x^4*y^20

The first factor is 4:  4y^2*x^4*y^20.  This is followed by the product of y^2 and y^20:                   4*y^22*x^4

Finally, this should be re-written as

                                    4*x^4*y^22

Another way of doing this problem would involve expanding the numerator fully and then cancelling out like factors:

8*x^6*y^30      4*x^4*y^22

----------------- = ------------------ = 4*x^4*y^22

  2x^2y^8                  1

7 0
2 years ago
Write each expression in radical form.<br> 1. 7²2. 4413
Oliga [24]

Answer:1. 7   2. \sqrt{4413}

Step-by-step explanation:

1. \sqrt{ 7^{2} = 7

2.\sqrt{4413} ( doesn't have any simplest radical form)

7 0
3 years ago
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